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Ksivusya [100]
3 years ago
7

What is the area of this figure?

Mathematics
2 answers:
Contact [7]3 years ago
8 0
I think the answer is 128. Hope it helps!
shutvik [7]3 years ago
6 0
The answer is 153 hope this helps 
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89 + 217 =<br> 1,564 – 1,438 =<br> 11 X 5 =<br> 72 : 8 =<br> 6 X 10 =<br> 88 + 8 =<br> 4,632-4,608 =
denpristay [2]

Answer:

use a calculator

7 0
3 years ago
A manufacturer knows that their items have a normally distributed lifespan, with a mean of 5.8 years, and
yarga [219]

Answer:

Less than 3.6 years.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 5.8 years, and  standard deviation of 1.7 years.

This means that \mu = 5.8, \sigma = 1.7

The 10% of items with the shortest lifespan will last less than how many years?

Less than the 10th percentile, which is X when Z has a p-value of 0.1, so X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 5.8}{1.7}

X - 5.8 = -1.28*1.7

X = 3.6

Less than 3.6 years.

4 0
3 years ago
The area of a circle is 22.68cm2.<br> Find the length of the radius rounded to 2 DP.
kipiarov [429]

Answer: r=2.69. Calculate the radius of circle:Round the number: r=2.69Answer: r=2.69

3 0
3 years ago
9d + 10c<br> how many terms are in this expression
bogdanovich [222]

Answer:

I think 2

Step-by-step explanation:

6 0
3 years ago
Order these numbers from least to greatest. 7.186 , 7211 , 14320 , 7.36
Ksivusya [100]
7.186<7.36<7211<14320.........
8 0
3 years ago
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