3 years ago

64^1/3=4 in logarithmic form

2 answers:

7 0

$b^{a} = c
\\ \\In\ logarithmic\ form\ it\ can\ be\ written\ as
\\ \\log_{b}c=a.
\\ \\ So.\ in\ our\ case
\\ \\64^{\frac{1}{3}}=4
\\ \\ log_{64}4=\frac{1}{3}$

makkiz [27]3 years ago

5 0

log 64 (4)=1/3 is the final answer

You might be interested in

(-2 1/8) -12 25/29 - 10/7=

bonufazy [111]

$\displaystyle\\-2\frac{1}{8}-12\frac{25}{29}-\frac{10}{17}=\\\\\\=-\frac{2\times8+1}{8}-\frac{12\times29+25}{29}-\frac{10}{17}=\\\\\\=-\frac{16+1}{8}-\frac{348+25}{29}-\frac{10}{17}=\\\\\\=-\frac{17}{8}-\frac{373}{29}-\frac{10}{17}=\\\\\\=-\frac{17\times29\times17}{8\times29\times17}-\frac{373\times8\times17}{8\times29\times17}-\frac{10\times8\times29}{8\times29\times17}=\\\\\\=-\frac{8381}{3944}-\frac{50728}{3944}-\frac{2320}{3944}=\\\\\\=\frac{-8381-50728-2320}{3944}=\frac{61429}{3944}$