-13/5 is between -1 and -2.<br> True<br> False

There are 3 boxes for green chips and 5 boxes for red chips. each box has the same number of chips in it. if there are a total o

Sauron [17]

Answer:

<h2>2 in each box of course</h2>

g= green chips r= red chips

3 boxes of green chips meaning for each box there are <em>2</em> chips so there are 6 green chips. 5 boxes of red chips meaning for each box there are two chips so there are 10 red chips and 6 g + 10r = 16 chips in total

Step-by-step explanation:

6 0

2 years ago

Matrix question help needed

kramer

The required matrix is:

$\left[\begin{array}{ccc}-25&17&0\\8&-1&3\\\end{array}\right]$

Step-by-step explanation:

We need to apply elementary row operation -2R₂+3R₁ tothe matrix:

$A=\left[\begin{array}{ccc}-3&5&2\\8&-1&3\\\end{array}\right]$

Multiplying Row 2 with -2 and Row1 with 3 and adding,

-9 15 6

-16 2 -6

----------

-25 17 0

After applying this operation, Row 1 will be changed while Row 2 will remain same because we get -2R₂+3R₁ -> R₁

The required matrix is:

$\left[\begin{array}{ccc}-25&17&0\\8&-1&3\\\end{array}\right]$

Keywords: Matrices, elementary row operation

Learn more about matrices at:

#learnwithBrainly

6 0

3 years ago

Explain how you write products when there are not enough digits in the product to place a decimal point

Anni [7]

If you there isn't enough digits to place, just add zeroes to product to make it a full product or don't even use a decimal point at all.

6 0

2 years ago

I will give the brainliest answer! Look at the formula for the volume of a rectangular prism. How does the surface area change i

Lynna [10]

Answer:

i guess the answer should be b

Step-by-step explanation:

surface area depends on the length and width but it doesn't depend on the height of a prism

3 0

3 years ago

Read 2 more answers

A manufacturing company has two retail outlets. It is known that 30% of all potential customers buy

aleksandrvk [35]

Answer:

(a) A y P(A) = 0.4 (b) $\bar{B}$ y $P(\bar{B})$ =0.5 (c) $\bar{A}$ ∪ $\bar{B}$ y P( $\bar{A}$ ∪ $\bar{B}$ ) = 0.9 (d) $\bar{A}$ ∩ $\bar{B}$ y P( $\bar{A}$ ∩ $\bar{B}$ )=0.2

Step-by-step explanation:

A was defined as the event that a potential customer, randomly chosen, buys from outlet 1 in the original problem statement. We know that B denotes the event that a randomly chosen customer buys from outlet 2. So

P( $A\cap \bar{B}$ ) = 0.3, P( $B\cap \bar{A}$ ) = 0.4 and P( $A\cap B$ ) = 0.1

(a) P(A) = P( $A\cap (B\cup\bar{B})$ ) = P( $A\cap B$ ) + P( $A\cap \bar{B}$ ) = 0.1 + 0.3 = 0.4

(b) P(B) = P( $B\cap (A\cup\bar{A})$ ) = P( $B\cap A$ ) + P( $B\cap \bar{A}$ ) = 0.1 + 0.4 = 0.5

P( $\bar{B}$ ) = 1-P(B) = 1-0.5 = 0.5

(c) The customer does not buy from outlet 1 is the complement of A, i.e., $\bar{A}$ , and the customer does not buy from outlet 2 is the complement of B, i.e., $\bar{B}$ , so, the customer does not buy from outlet 1 or does not buy from outlet 2 is $\bar{A}$ ∪ $\bar{B}$ and P( $\bar{A}$ ∪ $\bar{B}$ ) = P( $(A\cap B)^{c}$ ) by De Morgan's laws

P( $(A\cap B)^{c}$ ) = 1-P(A∩B)=1-0.1=0.9

(d) The customer does not buy from outlet 1 is the complement of A, and the customer does not buy from outlet 2 is the complement of B, so we have that the statement in (d) is equivalent to $\bar{A}$ ∩ $\bar{B}$ and P( $\bar{A}$ ∩ $\bar{B}$ ) = P( $(AUB)^{c}$ ) by De Morgan's laws, and

P( $(AUB)^{c}$ ) = 1-P(A∪B)=1-[P(A)+P(B)-P(A∩B)]=1-[0.4+0.5-0.1]=1-0.8=0.2

8 0

2 years ago

-13/5 is between -1 and -2. True False