Write the equation of the line in fully simplified slope-intercept form.

Triangle MNO is an equilateral triangle with sides measuring units. What is the height of the triangle? a) 12 units b) 24 units

Alecsey [184]

Answer:

The height of the equilateral triangle is 24 units

Step-by-step explanation:

In the question above, the unit of the side of the equilateral triangle is not given. If the complete question is:

Triangle MNO is an equilateral triangle with sides measuring 16 square root of 3 units, then the length of each side is 16√3 units.

To find the height of the triangle, we use Pythagoras theorem

MP^2 + PO^2 = MO^2

Let MP^2 be x

x^2 + {(16√3)/2}^2 = (16√3)^2

X^2 + (256*3)/4 = 256*3

4x^2 + 768 = 768* 4

4x^2 + 768 = 3072

4x^2 = 3072-768

4x^2 = 2304

X^2 = 2304/4

X^2 = 576

x= √576

x = 24 units

4 0

3 years ago

Read 2 more answers

Please solve-y(2+4y)

Elina [12.6K]

To solve this, you distribute the -y to both terms, 2 and 4y.
It will look something like this: (2*-y)+(4y*-y)
When you simplify, look for any like terms that can be combined, and if none, then leave it as it is.
Your final answer will be: -2y-4y^2

8 0

3 years ago

Answer all questions: 1) The electric field of an electromagnetic wave propagating in air is given by E(z,t) = 4cos(6 x 10^8 t -

Andre45 [30]

Answer:

8

Step-by-step explanation:

4 0

3 years ago

Andy was at Level –1 and took the elevator to Level 21. How many levels did the elevator move upward?

kramer

Answer: 22 Levels

Step-by-step explanation: He would need to go one level higher just to get to level one, and another 21 to get to the level that he wants to, so the total would be 22 levels.

7 0

3 years ago

Read 2 more answers

How do you solve x+4=10^x

raketka [301]

Two ways to solve the problem:

A. By graphing f(x)=10^x and g(x)=x+4.
The intersection(s) will be the solution.
See graph below, approximate solutions: (-4,0),(0.66, 4.67)

B. Refine approximate solutions using Newton's method
Let h(x)=f(x)-g(x) = 10^x-x-4 ...............(1)
we calculate the derivative, h'(x) = log(10)*10^x-1 [ note:log(x) means ln(x) ]
and use Newton's iterative formula to find successive approximations to the root, basically refining the approximate solutions.
The iterative formula for nth approximation $x_n$ is given by
$x_n$ = $x_{n-1}$ - h( $x_n$ ) / h'( $x_n$ )....(2)

Using initial approximation (-4,0), we have x0=-4
x1
=x0-h(x0)/h'(x0)
=-4 - h(-4)/h'(-4)
=-4 - (10^(-4)-(-4)-4)/(log(10*10^(-4)-1)
=-4 - (1/10000)/(log(10)/10000-1)
=-3.9999000

Repeating the same for second approximation, x2, we get
x2=-3.99989997696619 which is accurate to 14 places after decimal

Now we can refine the other approximate solution, x0=0.66 to find
x1=0.669356
x2=0.6692468481102326
x3=0.669246832877748
x4=0.6692468328777476
So we will accept x=0.669246832877748

So the solutions are S={-3.99989997696619,0.6692468328777476} both accurate to 14 places after the decimal

3 0

3 years ago