Answer:
Mildred is correct because she distributed 5 correctly
Step-by-step explanation:
We cannot tell exactly which solution goes with which student, but we believe you are saying ...
Mildred’s Solution:
5 (Negative 2 and one-fourth) = 5 (negative 2 minus one-fourth)
= negative 10 minus StartFraction 5 over 4 EndFraction
= negative 11 and one-fourth
This solution describes the correct distribution of 5. Whoever it belongs to gave the correct solution.
Answer:
0.375 pages per minute.
Step-by-step explanation:
Assuming that is 2 right triangles sharing a side
height^2 = 20^2 -7^2
height^2 = 400 - 49
height^2 = 351
height =
<span>
<span>
<span>
18.7349939952
</span>
</span>
</span>
x^2 = 24^2 - <span>18.7349939952^2
x^2 = 576 -351
x^2 = 225
x = 15
</span>
-3(y+2)^2-5+6y
-3(y^2+4y+4)-5+6y
-3y^2-12y-12-5+6y
-3y^2-6y-17
"Part A: What is the y-intercept of the function, and what does this tell you about the horse? (4 points)" The y-intercept is (0,8), which tells us that at the beginning the horse is 8 miles from the barn.
"Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. (4 points)" The value of the function at x=1 is 58 and that at x=3 is 158. Thus, the change in the horse's distance from the barn is 158-58, or 100 feet. The time period involved here is 2 sec. Thus, the average rate of change of the horse's position with respect to time is
100 feet
average rate of change = ---------------- = 50 ft/sec
2 sec
If the horse were to move steadily at a fixed rate from 58 feet to 158 feet from the barn, its average rate would be 50 ft/sec.
"Part C: What would be the domain of the function if the horse continued to walk at this rate until it traveled 508 feet from the barn? (2 points)"
Here time begins at x=0 and ends at x=4 sec. Thus, the appropriate domain here is [0,4] sec.
