Answer:
The answer is 40.5 which is D
Step-by-step explanation:
Answer:
0.5122 or 51.22%
Step-by-step explanation:
In a certain city, in June Probability of cloudy days = P(cloudy) = 0.41
Probability of cloudy and rainy = P(cloudy and rainy) = 0.21
Probability of rainy if we already know it is cloudy = ![\frac{\text{[P(cloud and rainy)]}}{[P(cloud)]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%5BP%28cloud%20and%20rainy%29%5D%7D%7D%7B%5BP%28cloud%29%5D%7D)
=
= 0.512195122 ≈ 0.5122
Therefore, the probability that a randomly selected day in June will be rainy if it is cloudy is 0.5122 or 51.22%
Jamie's claim isn't reasonable. This is because half of 4/5 is 4/10 and if you simplify it, it is 2/5.
<h3>165 degrees :) your welcome</h3>
Here:
PFA for the answers. The numbering might confuse you. It goes from the 1 to the last marked question in ascending order. Hope it helps you. ~BYE