To use De Moivre's theorem, we first write -2i is cis form: 0 - 2i has r = 2 and theta = 270.
Then we take the cube root, which means the new result will have r^(1/3), and the angle (theta/3). This means r = cbrt(2) and theta = 90.
This means that the answer is (cube root of 2)(cos90 + i*sin90), choice C.
I suspect the choices "3sqrt2" is actually a cube root of 2, not 3 multiplied by the square root of 2.
All rhombuses have 2 pairs of parallel sides.
I do not get it right now but i will answer it in a minute ok
The answer is D +14 because to negatives make a positive
(1/2,4) because that is where the two lines meet.