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What about 11 and 169

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yKpoI14uk [10]3 years ago

8 0

Answer:

Step-by-step explanation:68

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-2x+3y=-12<br> Can you show me how to work this problem?

Varvara68 [4.7K]

Change the signs on both sides of the equation 2x-3y-12=0

4 0

3 years ago

Read 2 more answers

[(7+3)x5-4](divided by) 2+3<br> SHOW ALL WORK WILL MARK BRAINLIEST <br> PLEASE HURRY

Mnenie [13.5K]

BIDMAS so do the 7+3 first = 10
[10 x 5 - 4] (divided by) (2+3)
then work out both brackets by doing the multiplication first
[10 x 5 - 4] = [50 - 4] = 46
(2 + 3) = 5
46 divided by 5 = 9.2

8 0

3 years ago

Read 2 more answers

A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses

mash [69]

Answer:

The original duration of the tour = 20 days

Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for $x$ days.

So, for $x$ days the total expense = $360

<em>Thus the daily expense in dollars can be given by</em> = $\frac{360}{x}$

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

<em>Tour duration now</em> = $(x+4)$ days

On extension, his daily expense is cut by $3

<em>New daily expense in dollars </em>= $(\frac{360}{x}-3)$

Total expense in dollars can now be given as: $(x+4)(\frac{360}{x}-3)$

Simplifying by using distribution (FOIL).

$(x.\frac{360}{x})+(x(-3)+(4.\frac{360}{x})+(4(-3))$

$360-3x+\frac{1440}{x}-12$

$348-3x+\frac{1440}{x}$

We know total expense remains the same which is = $360.

So, we have the equation as:

$348-3x+\frac{1440}{x}=360$

Multiplying each term with $x$ to remove fractions.

$348x-3x^2+1440=360x$

Subtracting $348x$ both sides

$348x-348x-3x^2+1440=360x-348x$

$-3x^2+1440=12x$

Dividing each term with -3.

$\frac{-3x^2}{-3}+\frac{1440}{-3}=\frac{12x}{-3}$

$x^2-480=-4x$

Adding $4x$ both sides.

$x^2+4x-480=-4x+4x$

$x^2+4x-480=0$

Solving using quadratic formula.

For a quadratic equation: $ax^2+bx+c=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging in values from the equation we got.

$x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}$

$x=\frac{-4\pm\sqrt{16+1920}}{2}$

$x=\frac{-4\pm\sqrt{1936}}{2}$

$x=\frac{-4\pm44}{2}$

So, we have

$x=\frac{-4+44}{2}$ and $x=\frac{-4-44}{2}$

$x=\frac{40}{2}$ and $x=\frac{-48}{2}$

∴ $x=20$ and $x=-24$

Since number of days cannot be negative, so we take $x=20$ as the solution for the equation.

Thus, the original duration of the tour = 20 days

6 0

3 years ago

I’m stuck can you please help

trapecia [35]

Sure !!! What do you need help with?

7 0

1 year ago

A movie theater is located on a map of a city represented by a coordinate plane. The location of the movie theater is at (−4, 2)

Romashka [77]

See the graph

<h2>Explanation:</h2>

Remember to write complete questions in order to get good and exact answers. Here you haven't provided any option, but it's easy to plot this point on a coordinate system in order to know the location of the movie theater. We know that this theater is at the point:

$(-4,2)$

So let's plot this point in the cartesian plane:

The x-coordinate is -4
The y-coordinate is 2.

So the graph is shown below. Remember that the horizontal axis is called the x-axis while the vertical axis is called the y-axis.

x > 0 for the x-values to the right of the origin.

x < 0 for the x-values to the left of the origin.

y > 0 for the y-values above the origin

y < 0 for the y-values below the origin.

<h2>Learn more:</h2>

Cartesian coordinate system: brainly.com/question/2141683

#LearnWithBrainly

7 0

3 years ago