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damaskus [11]
3 years ago
9

How to prove a number is an accumulation point of a set?

Mathematics
1 answer:
77julia77 [94]3 years ago
6 0

A number xx is said to be an accumulation point of a non-empty set <span>A⊆R</span><span>A<span>⊆R if every neighborhood of xx contains at least one member of AA which is different from xx.</span></span>

A neighborhood of xx is any open interval which contains xx.

<span><span>In this question, we have <span><span>A=Q</span><span>A=Q</span></span></span> and we need to show if <span>xx</span> is any real number then <span>xx</span> is an accumulation point of <span>QQ</span>. This is almost obvious because if <span>xx</span> is any specific real number then any neighborhood <span>BB</span> of <span>xx</span> contains infinitely many rational numbers (and hence at least one of them is different from <span>xx</span> itself).</span>

The fundamental property which we are using here is the following:

If <span>a<b</span><span>a<b</span> are two real numbers then there is a rational xx with <span>a<x<b</span><span>a<x<b</span> and an irrational number yy with <span><span>a<y<</span>b</span><span>a<y<b</span>.

<span> </span>

<span><span>This above fact implies that there are infinitely many rational and irrational numbers between <span>aa</span> </span>and <span>bb</span>. In other words any interval <span><span>(a,b)</span><span>(a,b)</span></span> contains infinitely many rational and irrational numbers. The neighborhood <span>BB</span> in my answer above is an interval of this type and hence contains many rational numbers.</span>

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