Answer:
I think the answer is 381.7
Answer:
the value of a, if points A and D belong to the x−axis and m∠BAD=60 degrees is 2/√3
Step-by-step explanation:
Trapezoid ABCD with height 2 unit contain Points A and D which may be A(-1,0) and D(5.0)
Vertex of parabola is the point where parabola crosses its axis
Let suppose A and D are two points then draw altitude on them CE where C is on AD
As height of altitude has been given that is 2 then
total angle = 180 degrees
m∠BAD=60 degrees
m∠CEA =180 - 60 -90
= 30
then the value for AE = 2/√3.
y=a(x+1)(x−5).
where 2/√3 is right of -1 and 2 unit above x-axis
Answer: Table A
Step-by-step explanation:
The coefficient of x^2 is 1, the coefficient of x is -6, and the constant is 0. This means that a = 1, b = -6, and c = 0.
- This eliminates tables B and C.
Now, we need to determine if the graph opens up or down to differentiate between A and B. Since the coefficient of x^2 is positive, the graph opens up.
- Thus the answer is <u>Table A.</u>
Answer:
wait huh?im confused lol
Step-by-step explanation:
Step-by-step explanation:
To write the equation in LaTeX in form y = ab^x or 
for y = abx .........(1)
(a) LaTeX: y=3\sqrt{4^{2x}} y = 3 4 2 x can be written in mathematical form as
; y = 342x
on comparing with equation (1) we get a =3 and b =4
⇒y = 34^x or 
(b) LaTeX: y=\frac{\sqrt[3]{5^{3x}}}{2} y = 5 3 x 3 2 can be written in mathematical form as
![y=\frac{\sqrt[3]{5^{3x}}}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B5%5E%7B3x%7D%7D%7D%7B2%7D)
; y = 342x
on comparing with equation (1) we get a =0.5 and b =5
⇒y = 
(c)LaTeX: y=8^{x+2} y = 8 x + 2 can be written in mathematical form as
on comparing with equation (1) we get a =64 and b =8
y = 
(d)LaTeX: y=\frac{3^{2x+1}}{\sqrt{3^{2x}}} can be written in mathematical form as
= 
= 
on comparing with equation (1) we get a =3 and b =3
y =
