Looking at the expression x² +8x-20,we can see that the first coefficient is 1, the second coefficient is 8 and the last term is -20. Now multiply the first coefficient (1) by the last term (-20) to get (1)·(-20)=-20. Now the question is: what two whole numbers multiply to -20 (the previous product). factors of -20: 1,2,4,5,10,20 -1, -2, -4, -5, -10, -20 note: list the negative of each factor. This will allow us to find all possible combinations. These factors pair up to multiply to -20. 1*(-20) = -20 2*(-10) = -20 4*(-5) = -20 (-1)*(20*) = -20 (-2)*(10* = -20 (-4)*(5) = -20 now let's add up each pair of factors to see if one pair adds to the middle coefficient:
From the table above, we can see that the two numbers -2 and 10 multipy to -20 and add up to 8. Now replace the middle term 8x with -2x+10x. Remember, -2 and 10 add up to 8. so this shows us that -2x+10x=8x.
x²+-2x+10x -20 Replace the second term 8x with -2x +10x. (x²-2x)+(10x-20) Group the terms into two pairs. x(x-2x)+(10x-20) Factor out the GCF x from the first group.
x(x-2)+10·(x-2) Factor out 10 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
(x+10)·(x-2) Combine like terms. Or factor out thge common term x-2. ----- ANSWER:
So, x² + 8·x -20 factors to (x+20)·(x-2. In other words, x² + 8·x-20=(x+10)·(x-2)
THIS IS HARD TO UNDERSTAND, BUT HOPE THIS HELPED YOU! AND HOPE YOU GET IT TOO!!! :D
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