Cost of ribeye steak dinner is $19.058
Cost of grilled salmon dinner is $14.88
Solution:
Let x be the ribeye steak dinner and y be the grilled salmon dinner.
Write the given equation in the algebraic form.
First day sold:
15x + 21 y = 598.34 – – – – (1)
Second day sold:
25x + 7y = 580.61 – – – – (2)
To solve these equations by elimination method.
Multiply equation (2) by 3, we get
75x + 21y = 1741.83 – – – – (3)
Now, subtract equation (1) from equation (3).
75x + 21y – (15x + 21y)= 1741.83 – 598.34
75x + 21y – 15x – 21y = 1143.49
60x = 1143.49
Divide by 60 on both sides of the equation.
x = 19.058
Substitute x value in equation (2), we get
25(19.058) + 7y = 580.61
476.45 + 7y = 580.61
Subtract 476.45 on both sides of the equation.
7y = 104.16
Divide by 7 on both sides of the equation.
y = 14.88
Cost of ribeye steak dinner is $19.058
Cost of grilled salmon dinner is $14.88.
