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notsponge [240]
2 years ago
6

If f(x) = x2 + 7, what is the equation for f'(x)?

Mathematics
1 answer:
denis23 [38]2 years ago
6 0

Answer:

2x

Step-by-step explanation:

\bullet\ (x^2)^{\prime}=2x\\\\\bullet\ (7)^{\prime}=0

\Longrightarrow f^{\prime }\left( x\right)  =\left( x^{2}+7\right)^{\prime }  =(x^2)^{\prime}+(7)^{\prime}=2x

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The x-intercept is what 'x' is when 'y' is equal to 0. So plug in 0 for 'y' and solve for 'x':

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\sf 4x=16

Divide 4 to both sides:

\sf x=4

So the x-intercept is (4, 0).

The y-intercept is what 'y' is when 'x' is equal to 0. So plug in 0 for 'x' and solve for 'y':

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