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3 years ago

What is the value of x? Show your work.

Mathematics

2 answers:

LuckyWell [14K]3 years ago

6 0

16 is the correct answer because 4 x -4=16 x=16 or -16

erma4kov [3.2K]3 years ago

5 0

Well they are similar by ASA
30/25=1.2
20*1.2=24
24=4x-4
28=4x
7=x

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PLEASE HELP ME FOR BRAINLIEST ANSWER An architect designs a rectangular flower garden such that the width is exactly two-thirds

Oksanka [162]

Answer:

Length: 84 ft

Width: 56 ft

Step-by-step explanation:

Let's define some variables first.

Call the length l and width w.

We know that w = 2/3l. Therefore, we can express w in terms of l with this expression.

Now, let's set up an equation. The flower garden is rectangular, and 280 feet of fencing are used to enclose the garden. This represents perimeter.

Remember the formula for perimeter of a rectangle: 2l + 2w

Let's substitute 2/3l for w:

2l + 2*2/3l = P

2l + 4/3l = 280

2 4/3l = 280

10/3l = 280

l = 84

Now, we know that the length is equal to 84 feet. We can multiply 84 feet by 2/3 to find the width.

84*2/3 = 56

Length: 84 ft

Width: 56 ft

Let's plug these values into the formula and see if they give us the correct perimeter:

2l + 2w = P

2*84 + 2*56 = P

168 + 112

= 280 feet

These are the correct dimensions!

Hope this helps! You can reach out to me if you have further questions or concerns! :)

6 0

3 years ago

The following data were collected from 12 rain gauges in a park. Build a 95% CI for the mean rainfall at the park.

dybincka [34]

Answer:

Critical values: $t_{\alpha/2}=-2.201$ $t_{1-\alpha/2}=2.201$

95% confidence interval would be given by (3.646;4.472)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The data is:

4.65 3.89 2.73 4.35 3.80 4.86 4.33 4.37 4.76 4.05 3.05 3.87

2) Compute the sample mean and sample standard deviation.

In order to calculate the mean and the sample deviation we need to have on mind the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$

=AVERAGE(4.65,3.89,2.73, 4.35, 3.8, 4.86, 4.33, 4.37, 4.76, 4.05, 3.05, 3.87)

On this case the average is $\bar X= 4.059$

=STDEV.S(4.65,3.89,2.73, 4.35, 3.8, 4.86, 4.33, 4.37, 4.76, 4.05, 3.05, 3.87)

The sample standard deviation obtained was s=0.6503

3) Find the critical value t* Use the formula for a CI to find upper and lower endpoints

In order to find the critical value we need to take in count that our sample size n =12 <30 and on this case we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by: