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puteri [66]
3 years ago
10

Write the phrase as a variable expression. Use x to represent "a number."

Mathematics
1 answer:
Ronch [10]3 years ago
5 0
None of these are correct, if it is asking for a number (x) divided by 45 the correct answer would be x/45
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What is the product of Three-fourths and Negative StartFraction 6 over 7 EndFraction? -9/14
Brums [2.3K]

Answer:

The product is :  -\frac{9}{14}

Step-by-step explanation:

First term given to us is =  \frac{3}{4}

Second term given to us = -\frac{6}{7}

We have to find product for term 1 and term 2

Which means that we have to find : (\frac{3}{4})\cdot(-\frac{6}{7})

Calculating the product of fraction is pretty simple. To calculate the product of any two fractions. We have to multiple the numerator of 1st term with numerator of 2nd which serves as the the numerator of the product. Similarly we have to multiply denominator with denominator.

(\frac{3}{4})\cdot(-\frac{6}{7}) = \frac{3\cdot(-6)}{4\cdot7} = -\frac{18}{28}

Reduce the fraction

-\frac{18}{28}= -\frac{9}{14}

3 0
3 years ago
Plz help due today tip and sales tax’s
ZanzabumX [31]
It’s is number 1 hope this helpeddd!!!!
3 0
3 years ago
Solves the inequality. Write your final answer in interval notation:<br><br> -3(2x+1) &gt; -2(x+6)
3241004551 [841]

-3(2x+1) > -2(x+6)

-6x -3 > -2x - 12


-6x -3+6x > -2x - 12+6x


-3>4x-12


-3+12>4x-12+12

9 > 4x

4x<9

x<4/9


(-∞, 4/9)

7 0
3 years ago
The product of 2 and 14 more than a number
Gelneren [198K]

Answer:

85

Step-by-step explanation:

6 0
3 years ago
Select the correct answer from each drop-down menu.
Alenkasestr [34]

Answer:

The points of intersections are: <u>(1.5 , 1.25) and (4 , 0)</u>

Step-by-step explanation:

Given:

y = x² - 6x + 8   ⇒ (1)

2y + x = 4         ⇒ (2)

And required the solution of the system of equations.

By graphing the system of equations, the points of intersections are:

<u>(1.5 , 1.25) and (4 , 0)</u>

See the attached figure.

<u>Another solution:</u>

By substitution of y from the second equation at the first equation.

From (1) ⇒ y = 0.5 (4-x)

At (2): and solve for x

0.5 ( 4 - x ) = x² - 6x + 8 ⇒ multiply both sides by 2

4 - x = 2x² - 12x + 16

2x² - 12x + 16 + x - 4 = 0

2x² - 11x + 12 = 0

The general solution of the quadratic equation:

x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

so, a = 2 , b = -11 and c = 12

∴x=\frac{-(-11) \pm \sqrt{(-11)^2-4*2*12} }{2*2}=\frac{11 \pm \sqrt{25} }{4} =\frac{11 \pm 5}{4} \\x = \frac{11+5}{4} = \frac{16}{4}=4\\  OR \  x = \frac{11-5}{4}=\frac{6}{4}=1.5\\

∴ at x = 4       ⇒ y = 0.5 (4-x) = 0.5 * 0 = 0

And at x = 1.5 ⇒ y  = 0.5 (4-x) = 0.5 * ( 4 - 1.5 ) = 0.5 * 2.5 = 1.25

<u>So, the solution are the points (4,0) and (1.5 , 1.25)</u>

6 0
3 years ago
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