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PilotLPTM [1.2K]
3 years ago
14

Simplify the expression: 7–3p+4p

Mathematics
2 answers:
Nadya [2.5K]3 years ago
7 0

Answer and Step-by-step explanation:

The simplified expression is:

<u>7 + p</u>

<u></u>

because we subtract 3p from 4p.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

trapecia [35]3 years ago
6 0

Answer:

7 + p

Step-by-step explanation:

Solve:

7 - 3p + 4p

Simplify using like terms

Wrote problem using addition

7 + ( -3p + 4p)

7 + 1p or 7 + p

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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The correct answer is A
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PLEASE HELP
kifflom [539]

\\ \sf\longmapsto \dfrac{x^2-1}{x^2+5x+4}\leqslant 0

  • Solving denominator

\\ \sf\longmapsto x^2+5x+4>0

\\ \sf\longmapsto x^2+4x+x+4>0

\\ \sf\longmapsto x(x+4)+1(x+4)>0

\\ \sf\longmapsto (x+4)(x+1)>0

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7 0
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Find the quotient of 2/5 and 4/5<br> Give your answer as a fraction in its simplest form.
mixer [17]

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Step-by-step explanation:

3 0
4 years ago
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Determine whether each relation is a function. Give the domain and range for each relation.
brilliants [131]

Answer:

Not a function

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Range: {4,5}

Step-by-step explanation:

A function is a relation where each input has its own output. In other words if the x value has multiple corresponding y values then the relation is not a function

For the relation given {(3, 4), (3, 5), (4, 4), (4, 5)} the x value 3 and 4 have more than one corresponding y value therefore the relation shown is not a function

Now let's find the domain and range.

Domain is the set of x values in a relation.

The x values of the given relation are 3 and 4 so the domain is {3,4}

The range is the set of y values in a relation

The y value of the given relation include 4 and 5

So the range would be {4,5}

Notes:

The values of x and y should be written from least to greatest when writing them out as domain and range.

They should be written inside of brackets

Do not repeat numbers when writing the domain and range

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