That would be the commutative property
Answer:
Algebra
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How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
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Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
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For questions #6 & #8, you didn't complete them or provide all necessary things (such as description, data, or graph). 5 − ≤ 20 is not an inequality, an inequality should be something like 5 - x ≤ 20, but you didn't give anything like that in your question.
7. (-1,4), (5,2), we can calculate the slope. As x increases from -1 to 5, (increases by 6), the y-value decreases by 2. -2/6 = -1/3, the slope is -1/3. The slope is negative and the y-value decreases by a third of the amount the x-value changes.
9. C, because you can only hold at MOST 500, and larger watermelons is represented by 10x. I'm assuming you made an error in your question, you gave me the values of larger/smaller watermelons only, and your question asked for larger & medium and the options seem to suggest there's only larger/smaller. 10x + 3y <= 500 or <, smaller than or equal would be the better choice if available.
10. y = 2x + 10, because 2 is the slope as minutes increase by 1, inches increase by 2, and the 10 inches of sawdust are already there.
When you offer Questions #6 & #8's data, I'll gladly help you with it. The rest of the questions are correct and properly explained.
Answer:

Step-by-step explanation:
The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".
Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that 
The probability mass function for the random variable is given by:

And f(x)=0 for other case.
For this distribution the expected value is the same parameter 

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

Using the pmf we can find the individual probabilities like this:


And replacing we have this:
![P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^{-\lambda} +\lambda e^{-\lambda}[]](https://tex.z-dn.net/?f=P%28X%5Cgeq%202%29%3D1-%5BP%28X%3D0%29%2BP%28X%3D1%29%5D%3D1-%5Be%5E%7B-%5Clambda%7D%20%2B%5Clambda%20e%5E%7B-%5Clambda%7D%5B%5D)

And we want this probability that at least of 99%, so we can set upt the following inequality:

And now we can solve for 

Applying natural log on both sides we have:



Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.
Using the Newthon Raphson method, we apply this formula:

Where :


Iterating as shown on the figure attached we find a final solution given by:
