2 years ago

Find the 10th term of the geometric sequence 1, 3, 9, ...

Mathematics

1 answer:

ladessa [460]2 years ago

3 0

Answer:

a(10) = 3^9 = 19683

Step-by-step explanation:

In this sequence each new term is equal to 3 times the previous term. Thus, 3 is the common ratio. The first term is 1.

The general formula for the nth term of a geometric sequence i

a(n) = a(1)*r^(n -1), where r is the common ratio.

Here, a(n) = 1*3^(n - 1), and so

the 10th term is

a(10) = 1*3^(10 - 1), or

a(10) = 3^9 = 19683

You might be interested in

Whats one and half times 16

malfutka [58]

Okay so $1 \frac{1}{2}*16$ .

First, we make 16 a fraction: $16=\boxed{\boxed{ \frac{16}{1}}}$

Then, we make $1 \frac{1}{2}$ a improper fraction: $1 \frac{1}{2}= \frac{1*2+1}{2}=\boxed{\boxed{ \frac{3}{2}}}$

Now, we multiply $\frac{3}{2}$ by $\frac{16}{1}$ : $\frac{3}{2}* \frac{16}{1}= \frac{48}{2}$

Finally, we simplify $\frac{48}{2}$ : $\frac{48:2}{2:2}= \frac{24}{1}=\boxed{\boxed{24}}}$ .

Your answer is $\boxed{\boxed{24}}}}$ .

Hoped I helped. :)

3 0

3 years ago

Read 2 more answers

3x + 5=. X equals six

horsena [70]

Answer:

Step-by-step explanation:

3 (6) + 5 =

You would have to multiply first

So,

Then add

8 0