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Annette [7]
2 years ago
15

What is the Identity Property of Multiplication?

Mathematics
2 answers:
Scilla [17]2 years ago
7 0

Answer:

The identity property of multiplication, also called the multiplication property of one says that a number does not change when that number is multiplied by 1. Ex. 12x1=12

Hunter-Best [27]2 years ago
3 0

Answer:

Identity property of multiplication: The product of 1 and any number is that number. For example, 7 × 1 = 7 7 \times 1 = 7 7×1=77, times, 1, equals, 7.

Step-by-step explanation:

PLZZ MARK AS BRAINLIEST!!!!

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Easton wants to put a variety of donuts in a display case. The case is large enough to hold 100 donuts. Complete the table below
shutvik [7]

The amounts for each donut are given as follows:

  • Strawberry: 15.
  • Chocolate: 45.
  • Sprinkle: 40.

<h3>How to obtain the amounts?</h3>

The amounts for each donut are found applying the proportion, multiplying the decimal equivalent of each percentage by the total number of donuts.

From the problem, the total number of donuts is given as follows:

100 donuts.

The percentages of each type of donuts are given as follows:

  • Strawberry: 15%.
  • Chocolate: 45%.
  • Sprinkle: 40%.

The decimal equivalent of each percentage is given as follows:

  • Strawberry: 0.15.
  • Chocolate: 0.45.
  • Sprinkle: 0.4.

Hence the amounts are given as follows:

  • Strawberry: 15, as 0.15 x 100 = 15.
  • Chocolate: 45, as 0.45 x 100 = 45.
  • Sprinkle: 40, as 0.4 x 100 = 40.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

3 0
1 year ago
Find area of the figure
kirza4 [7]

Answer:

70 sq. in

Step-by-step explanation:

Area of the figure

= ( 10 x 5 ) + ( 5 x 4 )

= 50 + 20

= 70

= 70 sq. in

7 0
2 years ago
Evaluate tan ( cos^-1 ( 1/8 ) ) , giving your answer as an exact value (no decimals)
vekshin1

\bf cos^{-1}\left( \cfrac{1}{8} \right)=\theta \qquad \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{8}}\impliedby \textit{let's find the \underline{opposite}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{8^2-1^1}=b\implies \pm\sqrt{63}=b ~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\pm\sqrt{63}}}{\stackrel{adjacent}{1}} \\\\\\ ~\hspace{34em}


\bf \stackrel{\textit{keeping in mind that}}{tan\left(cos^{-1}\left( \frac{1}{8} \right) \right)}\implies tan(\theta )

5 0
2 years ago
If you wanted to make the graph of y = 8x - 10 less steep, as well as shift the
azamat

Answer:

4x-15=y

Step-by-step explanation:

The higher the rise over the run the more steep your slope will be thus 4x is less steep than 8x because it does not rise as much.

The y intercept shifted downward means anything (-10>b) can be plausible for b.

3 0
3 years ago
478 divided 16 using partial quotients
Elena-2011 [213]
29.875 this is ur answer
5 0
3 years ago
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