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Evgesh-ka [11]
3 years ago
7

-4х + 5y=— 28 4x – 3y = 20

Mathematics
1 answer:
ZanzabumX [31]3 years ago
3 0

I hope it's correct and it helps I don't know how to explain it lol

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There are 13 cards of each suit in a deck of 52 cards (13 hearts, 13 diamonds, etc.). What is the probability of
lord [1]

We want to find the probability of randomly drawing a diamond card from a standard deck. We will find that the probability is P = 1/4.

So because we draw a card randomly, every card has the same probability of being drawn. Then the probability of randomly drawing a diamond card is equal to the quotient between the number of diamond cards and the total number of cards.

There are 13 diamond cards and a total of 52 cards, then the probability is:

P = 13/52 = 1/4

If you want to learn more about probability, you can read:

brainly.com/question/15246027

5 0
2 years ago
What are the three types of triangles, based on ANGLES?<br> Draw an example for each one.
artcher [175]

Answer:

Right Triangle, Acute Triangle, and Obtuse Triangle

Step-by-step explanation:

I can't draw it here but the right triangle has a side of 90°.

An acute triangle has a side smaller than 90°.

An obtuse triangle has a side bigger than 90°.

5 0
3 years ago
For x = -2, evaluate f(g(x)) - f(0), given that: f(x) = 2x + 5 g(x) = 4x​
Veronika [31]

Answer: -16

Step-by-step explanation:

f(g(x)) = 2(4(-2)) + 5

f(g(x)) = 2(-8) + 5

f(g(x)) = -16 + 5

f(g(x)) = -11

f(0) = 2(0) + 5

f(0) = 5

f(g(x)) - f(0) = -11 - 5

f(g(x)) - f(0) = -16

7 0
3 years ago
Help me please , Write the slope intercept of the given line, provide the submit solution
Dmitry [639]

Answer:

y=1/3x + 2

Step-by-step explanation:

the y intercept is 2 since that's where the line crosses and the x intercept is at 4

6 0
2 years ago
What times what equals 120 and adds up to 14
sesenic [268]
No solution; 14/2 = 7; 7^2 = 49; 49 < 120
the 2 numbers that add up to 14 that would give the largest product is less than 120
maybe you mean 120 is negative?
idk i might be wrong
3 0
3 years ago
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