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2 years ago

I’m Dum And Clueless Help

Mathematics

1 answer:

emmainna [20.7K]2 years ago

7 0

Answer:

-3a-4b+5

Step-by-step explanation:

(3a-6b+12)-(6a-2b+7)

3a-6b+12-6a+2b-7

3a-6a-6b+2b+12-7

-3a-4b+5

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7 Which is the best estimate for the percent equivalent of 75? 219 229 469 479

Natalka [10]

469 is the perece to equivalent to 75 becuase it’s bigger

3 0

2 years ago

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

3 years ago

Help!!! 10 PTS!!!

Crank

Answer:

This is actually pretty easy just find the intersecting points from the lines

Number of solutions: 2

What are the solutions: (4,5) and (0,-3)

7 0

2 years ago

What is the value of x

Afina-wow [57]

Answer:

Step-by-step explanation:

Sin(30) = LJ/8sqrt(3)

Sin 30 = ½

LJ = 4sqrt(2)

LM = JM = x

x² + x² = (4sqrt(2))²

2x² = 32

x² = 16

x = 4

6 0

3 years ago

You increase the size of a page by 30%. Then you decrease it by 30%. What is the size of the page now?

kotegsom [21]

Lets use 1 to solve this problem because it is easiest to show.

Multiply 1 by 1.3 for a 30% increase (1*1.3=1.3).

Then multiply 1.3 by .7 for a 30% decrease. (1.3*.7=.91)

Therefore the page had a 9% reduction from its original size or is 91% of its original size.

8 0

2 years ago

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