Solve by using sign chart 1/5k-1<1/10k-2-k-5/10k-2
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Answer:
We have four functions:
For f(x) we have two points (-2,2) and (-1,-1)
we will use two point form which is:
So, on substituting the values we get:
So, f(x)=-3x-4
We have g(x)=3x-4
Now, we will from h(x) we have two points let initial point on monday is (0,4) and tuesday (1,1) again use two point form we get:
So, h(x)= -3x+4
Now, we will form j(x) we have three points (2,10) , (-2,6) and (2,22)
We will use (-2,6) and (2,22) to find the function with two point form.
j(x)= 4x+14
To find the slope we will compare the given function with general equation which is y= mx +c; m is the slope
And to find y-intercept we will put x=0
f(x)=-3x-4
Slope is: -3
And y-intercept is: (0,-4)
g(x)=3x-4
Slope is: 3
And y-intercept is: (0,-4)
h(x)= -3x+4
Slope is: -3
And y-intercept is: (0,4)
j(x)= 4x+14
Slope is: 4
And y-intercept is: (0,14)
I’m getting (8 3/10 )
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