3 years ago

Twice the sum of a certain number and 26 is 72

Mathematics

1 answer:

katen-ka-za [31]3 years ago

3 0

Answer:

The unknown number is 12

Step-by-step explanation:

2(x+26)=76

or,x+26=76÷2

or,x=38-26

Therefore,x=12.

You might be interested in

Original price $90 markdown 24%

Gre4nikov [31]

The markdown will be $21.60. so the final price after the markdown is $68.40.

8 0

3 years ago

Identify the DELETION mutation from the following DNA sequence:ATG CCA AAT

Umnica [9.8K]

Answer

Hello, There!

:Identify the DELETION mutation from the following DNA sequence

ATG CCA AAT.

Hope this helps!

4 0

3 years ago

Bailey will roll a number cube and flip a coin for a probability experiment. The faces of the number cube are labeled 1 through

Tresset [83]

Heads it’s lucky i think but yeetr

6 0

3 years ago

Solve for x: 2/3+1/3x=2x

velikii [3]

Answer:

x=2/5 or

x=0.4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How would I solve this Rational Equation? <br><br>Solve for all values of x.

Nesterboy [21]

9514 1404 393

Answer:

x = 4

Step-by-step explanation:

I like to put these in the form f(x) = 0. We can do that by subtracting the right side. Common factors can be cancelled from numerator and denominator, provided they are not zero.

$\dfrac{7}{x+3}+\dfrac{3}{x-3}-\dfrac{x}{x-3}=0\\\\ \dfrac{7(x-3)+(x+3)(3-x)}{(x+3)(x-3)}=0\\\\\dfrac{(x-3)(4-x)}{(x-3)(x+3)}=0\\\\ \dfrac{4-x}{x+3}=0\qquad x\ne3\\\\x=4 \qquad\text{equate the numerator to zero, add $x$}$

_____

If you leave the numerator as (x-3)(4-x), then there are two values of x that make it zero. Because x=3 makes the equation "undefined", it cannot be considered to be a solution.

4 0

3 years ago