Given
x^5*k=a .................(1)
x^2*k=b .................(2)
We need to find x^3.
Solution:
On inspection, we note that (1)/(2) gives x^3 on the left hand side, but the division is valid on conditions that x ≠ 0 and k ≠ 0.
So we conclude:
(1) / (2)

=>

=>
on condition that
and
4 is a solution to the equation. It is true.
Y=1/2x+2 can i get brainliest
5000, take 3500 multiplied by 2/7 to find the amount of money deposited per month which is 1000 then multiply it by 5 to find the deposit over 5 months