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vlabodo [156]
3 years ago
5

16. Solve. Circle one. 5t- 5 = 5t+7 i’m so confused

Mathematics
2 answers:
Viefleur [7K]3 years ago
8 0

Answer:

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

Step-by-step explanation:

DIA [1.3K]3 years ago
8 0

Answer:

there are no solutions hope this helps

Step-by-step explanation:

5t−5=5t+7

Step 1: Subtract 5t from both sides.

5t−5−5t=5t+7−5t

−5=7

Step 2: Add 5 to both sides.

−5+5=7+5

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[39 POINTS] <br> If <img src="https://tex.z-dn.net/?f=%20x%5E5k%3Da%5C%5C%20x%5E2k%5E2%3Db%20" id="TexFormula1" title=" x^5k=a\\
rjkz [21]

Given

x^5*k=a .................(1)

x^2*k=b .................(2)

We need to find x^3.

Solution:

On inspection, we note that (1)/(2) gives x^3 on the left hand side, but the division is valid on conditions that x &ne; 0 and k &ne; 0.

So we conclude:

(1) / (2)

\frac{x^5*k}{x^2*k^2} = \frac{a}{b}

=>

\frac{x^3}{k} = \frac{a}{b}

=>

x^3= \frac{ak}{b} on condition that x\ne{0} and k\ne{0}



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