The equation, in slope-intercept form, of the line that is perpendicular to the line y- 4 = -(x-6) and passes through the point (-2,-2) is y = x.
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<h3>How to represent equation in slope intercept form?</h3>
The equation in slope intercept form is represented as follows;
y = mx + b
where
Therefore,
perpendicular lines follows the rule as follows;
m₁m₂ = -1
Therefore,
y - 4 = -(x - 6)
y - 4 = -x + 6
y = -x + 6 + 4
y = -x + 10
Therefore,
-1m₂ = -1
m₂ = 1
Hence, the line passes through (-2, -2).
Therefore,
-2 = 1(-2) + b
b = -2 + 2
b = 0
Therefore, the equation is as follows;
y = x
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take 6 plus 11 = 17 so 17 and above
It's simple, you just have to times everything. 5000 x 3.2% x 5 years. After calculating these, 3.2 is as 0.032 so there would be three decimal places. So then it will e 5000 x 0.032 x 5
Slope is a constant rate of change; change in y over change in x; rise over run; represented by the variable m. Point slope is the equation of a straight line in the form y − y1 = m(x − x1) where m is the slope of the line and (x1, y1) are the coordinates of a given point on the line.
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I think it’s either 180 or 360