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Blababa [14]
3 years ago
12

What is 2p + (3q + 2) = (2p + 3q) + 2

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0

Answer:

associative property of addition

Step-by-step explanation:

2p + (3q + 2) = (2p + 3q) + 2

There are no terms that can be combined since there are no like terms

We are using the associative property to move the parentheses from one  group of terms to the other.

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In a line of students. Jenna is number 8. The teacher says that a rule for a number patter is add 4. The first student in line s
tatyana61 [14]
She says 35 because number 7 in line says 31, so 31+4=35...

I hope this helped you!
7 0
3 years ago
Ayo i need help this is vv hard or i’m jus dumb.
erastovalidia [21]
It goes straight up I hope this helps if not in sorry
4 0
2 years ago
A bill from a plumber was $306 The plumber charged $150 for parts and $52 per hour for labor. How long did ths plumber work at h
ludmilkaskok [199]
We can make an equation from this.
Our intial value is 150 for parts, and he works for 52 dollars an hour.
We can define <em /><em>h</em> for hours and <em /><em>c</em> for total cost.
Therefore, we have:
c = 150 + 52h.
We can set this equal to 306 dollars, as that's the given total cost:
306 = 150 + 52h
Subtract 150 from both sides:
52h = 156
Divide both sides by 2:
h = 3
He worked 3 hours.
hope this helped!

6 0
3 years ago
1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
A store is instructed by corporate headquarters to put a markup of 25​% on all items. An item costing ​$16 is displayed by the s
tigry1 [53]

Answer:

$20

Step-by-step explanation:

the manager's error could likely be putting the percentage mark up rather than the markup price added to the original price

25%×16

= $4

mark up price= (16+4)$

= $20

7 0
2 years ago
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