B)$20 but also dam these mother truckers are broke.
Your answer should be A. i may be wrong, but my work calculated to a negative
Actually the position function with respect to time under constant acceleration is:
a=g
v=⌠g dt
v=gt+vi
s=⌠v
s=gt^2/2+vit+si
So if vi and si are zero then you just have:
s=gt^2/2
Notice that it is not gt^2 but (g/2) t^2
So the first term in any quadratic is half of the acceleration times time squared because of how the integration works out...
Anyway....
sf=(a/2)t^2+vit+si
(sf-si)-vit=a(t^2)/2
2(sf-si)-2vit=at^2
a=(2(sf-si)-2vit)/t^2 and if si and vi equal zero
a=(2s)/t^2
The 99.87th percentile, or the area to the left of the 3 standard deviation mark it 99.87% better than everyone/everything else.
Answer:
Step-by-step explanation:
<u>3n+2 is divisible by p:</u>
<u>8n+3 is divisible by p:</u>
<u>Solve each equation for n:</u>
- n = (px - 2)/3
- n = (py - 3)/8
<u>Eliminate n and solve for p:</u>
- (px - 2)/3 = (py - 3)/8
- 8(px - 2) = 3(py - 3)
- 8px - 16 = 3py - 9
- 8px - 3py = 7
- p = 7/(8x - 3y)
As we see p could get 1 or 7 as natural number. Since 1 is excluded, the only solution is 7, and 8x - 3y must equal to 1.
