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3 years ago

14

How do you find the square root of a whole number which are not perfect square

1 answer:

Gre4nikov [31]3 years ago

8 0

Answer: Finding the square root of numbers that aren't perfect squares

Divide: Divide the number that you are finding the squared root for with the number you picked in step 1. Average: Take the average of the number you got in step 2 and the square root. Repeat: Repeat steps 2 and 3 until the number is accurate enough for you.

Step-by-step explanation:

BRAINLESS PLEASE

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Question 6(Multiple Choice Worth 1 points)

Dafna11 [192]

Answer:

O The value of f(2) is smaller than the value of f(1).

Step-by-step explanation:

First, let's solve for both. When the problem says f(1) or f(2), this just means that the x value is equal to that. So:
f(1) = -5(1)^2 + 2(1) + 9 = 6
f(2) = -5(2)^2 + 2(2) + 9 = -7
Since f(1) = 6 and f(2) = -7, we know that f(1) is greater than f(2). Therefore, the value of f(2) is smaller than the value of f(1)

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2 years ago

What are two ways that you can find the surface area of a prism

3241004551 [841]

Answer:

Step-by-step explanation:

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3 years ago

A vertical pole is supported by a wire that is 26 feet long. If the wire is attached to the ground 24 feet away from the base of

Andrei [34K]

The answer is in the attachment

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2 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

Help plz:)))I’ll mark u Brainliest

zaharov [31]

Answer:

x = 13.4

Step-by-step explanation:

Use the Pythagorean Theorem

a² + b² = c²

x² + 6.8² = 14.1²

x² = 14.1² - 6.8²

x² = 152.57

Take the square root of both sides

x = 12.3519229272

Rounded

x = 13.4

7 0

2 years ago