Answer:
By exterior angle theorem, we have;
∠DBE = ∠H + ∠HEB = ∠ECD = ∠H + ∠HDC
∴ ∠H + ∠HEB = ∠H + ∠HDC
By addition property of equality, we have
∠HEB = ∠HDC
∠H = ∠H by reflexive property
∴ ΔHCD ~ ΔHEB by Angle Angle AA similarity postulate
∴ HE/HD = EB/DC, by the definition of similarity
Therefore, by cross multiplication, we have;
HE × DC = EB × HD
Therefore, by commutative property of multiplication, we have;
HE × DC = HD × EB
Step-by-step explanation:
We know that
in the first triangle
the ratio of the legs are
4.5/1.5-----> 3
then
case <span>A) 6 m and 2 m ------> ratio=6/3----> 3
so
</span><span>the legs of a second triangle are proportional to the lengths of the legs of the first triangle
</span>case B) 8 m and 5 m ------> ratio=8/5---->1.6
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle
case C) 7 m and 3.5 mm ------> ratio=7/3.5---->2
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle
case D) 10 m and 2.5 m ------> ratio=10/2.5---->4
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle
case E) 11.25 m and 3.75 m ------> ratio=11.25/3.75---->3
so
the legs of a second triangle are proportional to the lengths of the legs of the first triangle
the answer is
A) 6 m and 2 m
E) 11.25 m and 3.75 m
25 would be the nearest to your question and complete 100 with the 4
Answer:
45
Step-by-step explanation:
avg=42+43+46+49/4
avg=180/4
n=45
Answer:i have no idea but go back to your math book and lesson and check :p
Step-by-step explanation:
