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3 years ago

Kyle has $1500 to invest in a saving's account for 5 years. He has 3 options:

Mathematics

1 answer:

Snezhnost [94]3 years ago

4 0

Answer:

bank c

Step-bby-step explanation:

It's obvious that compound interest will give you more money than simple and therefore we can eliminate bank A

It's best to have your interest compounding as often as possible and because that's the only difference between bank B and C bank C is the best

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How many ways can you choose 4 cookies from a cookie jar containing 25 cookies of all the same type?

andre [41]

Answer:

Only one.

Step-by-step explanation:

Given that there are 25 cookie of the same type in a cookie jar.

We have to select 4 cookies from these 25.

Since they are all the same type, they are identical.

The question is

How many ways can you choose 4 cookies from a cookie jar containing 25 cookies of all the same type?

There is no difference if we take any four cookies from these 25.

Hence no of different ways = 1

Only one is the answer.

6 0

4 years ago

Read 2 more answers

Solve the equation for all real solutions. 25q2 + 15q +1 = 5q

ElenaW [278]

Answer:

i think the answer is 41

Step-by-step explanation:

because 25 +15=40+1=41 that's why i think its 41

7 0

3 years ago

The leopard weighed 50000 grams less than the baby elephant .the baby elephanr weighed 200000 gram less than the lion. If the li

Agata [3.3K]

Answer:

91287

Step-by-step explanation:

200,000-341287-50,000=91287

4 0

3 years ago

What is the equation for the line in slope-intercept form? will give brainliest

andriy [413]

Answer:

y = 8x

Step-by-step explanation:

The slope is 8, the y-intercept is 0. The slope-intercept form is written:

y = mx + b

So this situation would be written y = 8x + 0 or just y = 8x.

Hope it helps!

7 0

3 years ago

Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

3 0

2 years ago