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dezoksy [38]
3 years ago
15

Hector has a toy train that is 68 centimeters long. He puts a 23 centimeters caboose at the end. How long is the train with the

caboose?
Mathematics
2 answers:
Serhud [2]3 years ago
7 0

Answer:

91

Step-by-step explanation:

68+23=91

Nikitich [7]3 years ago
5 0

Answer: 91 centimeters

Step-by-step explanation:

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  Please help this is due today please i really need help it’s due in 4 hours!!!
Anarel [89]

Answer:

y=36 and X=44

Step-by-step explanation:

7 0
2 years ago
Calculate the value of 3x + 4y when x = -6 and y = 5.
MArishka [77]

Answer:

x = -6

-18+4y=0 => 4y=18 =>y=18/4=9/2

Y=5

3x+20=0 => x=3x= -20=> x= -20/3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the next fraction in each of the following patterns?1/40,4/40,9/40,16/40,25/40...?
tresset_1 [31]
Let
a1=1/40
a2=4/40
a3=9/40
a4=16/40
a5=25/40
a6=?

we know that
a2-a1=4/40-1/40----> 3/40
a3-a2=9/40-4/40-----> 5/40
a4-a3=16/40-9/40----> 7/40
a5-a4=25/40-16/40---> 9/40

the difference is
3/40,5/40,7/40.9/40,....
3/40+[2/40]---> 5/40
5/40+[2/40]---> 7/40
7/40+[2/40]---> 9/40

the next will be
9/40+[2/40]-----> 11/40
so
the next term is 25/40+[11/40]------> 36/40

the answer is
36/40
5 0
3 years ago
Given f(x) = x + 3x + 2 and g(x) = x + 1, perform the indicated operations. In the
nadezda [96]

Answer:  x² + 4x + 3

<u>Step-by-step explanation:</u>

   f(x) = x² + 3x + 2

+  <u>g(x) =          x + 1   </u>

(f+g)(x) = x² + 4x + 3

Note: This answer is based on f(x) having an x² (since the squared is missing from your question).

5 0
3 years ago
The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
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