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Akimi4 [234]
1 year ago
15

If it is known that a+b/a-b=c, find the following: 2a-2b/5a+5b

Mathematics
1 answer:
Olin [163]1 year ago
4 0

Answer:

\frac{2a-2b}{5a+5b} =\frac{2}{5c}

Step-by-step explanation:

\frac{a+b}{a-b} =c

\Longleftrightarrow \frac{a-b}{a+b} =\frac{1}{c}

\Longleftrightarrow \frac{2}{5} \times \frac{a-b}{a+b} =\frac{2}{5} \times \frac{1}{c}

\Longleftrightarrow  \frac{2\times(a-b)}{5\times(a+b)} = \frac{2\times1}{5\times c}

\Longrightarrow \frac{2a-2b}{5a+5b} =\frac{2}{5c}

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3 years ago
2 What is the constant in the expression 8x3 + 5 + 7x2 + 6x?<br> A 8<br> B 5<br> C 7<br> D 6
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4 0
3 years ago
Read 2 more answers
Hi does anyone know how to solve this question if so please show the working out.
tester [92]

Explanation:

The Law of Sines is your friend, as is the Pythagorean theorem.

Label the unmarked slanted segments "a" and "b" with "b" being the hypotenuse of the right triangle, and "a" being the common segment between the 45° and 60° angles.

Then we have from the Pythagorean theorem ...

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  b = √24

From the Law of Sines, we know that ...

  b/sin(60°) = a/sin(θ)

  y/sin(45°) = a/sin(φ)

Solving the first of these equations for "a" and the second for "y", we get ...

  a = b·sin(θ)/sin(60°)

and ...

  y = a·sin(45°)/sin(φ)

Substituting for "a" into the second equation, we get ...

  y = b·sin(θ)/sin(60°)·sin(45°)/sin(φ) = (b·sin(45°)/sin(60°))·sin(θ)/sin(φ)

So, we need to find the value of the coefficient ...

  b·sin(45°)/sin(60°) = (√24·(√2)/2)/((√3)/2)

  = √(24·2/3) = √16 = 4

and that completes the development:

  y = 4·sin(θ)/sin(φ)

6 0
3 years ago
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