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IgorC [24]
3 years ago
13

What number cube has faces numbered 1 to 6.

Mathematics
1 answer:
mars1129 [50]3 years ago
5 0

Answer:

I don`t see the attachment

Step-by-step explanation:

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What are the domain and range of f(x)-[x-2] +1
svetlana [45]
Replace <span><span>f<span>(x)</span></span><span>f<span>(x)</span></span></span> with <span>yy</span>.<span><span>y=<span>x2</span>−1</span><span>y=<span>x2</span>-1

</span></span>Interchange the variables.<span><span>x=<span>y2</span>−1</span><span>x=<span>y2</span>-1

</span></span>Solve for <span>yy</span>.
<span><span>y=<span>√<span>1+x</span></span>,−<span>√<span>1+x</span></span></span><span>y=<span>1+x</span>,-<span>1+x

</span></span></span>Solve for <span>yy</span> and replace with <span><span><span>f<span>−1</span></span><span>(x)</span></span><span><span>f<span>-1</span></span><span>(x)</span></span></span>.
<span><span><span>This is your answer=f<span>−1</span></span><span>(x)</span>=<span>√<span>1+x</span></span>,−<span>√<span>1+x</span></span></span><span><span>f<span>-1</span></span><span>(x)</span>=<span>1+x</span>,-<span>1+x
Hope you have a wonderful day! hope this helps!



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7 0
3 years ago
The area of the green square is 9 ft? The area of the red square is 16 ft?
Drupady [299]
The green square is 18 and the red is 32
5 0
3 years ago
Please help with this question.
andrew11 [14]

Answer:

p3+13=37

We move all terms to the left:

p3+13-(37)=0

We add all the numbers together, and all the variables

p^3-24=0

7 0
3 years ago
Solve for x if the angles are 110 and 2x+3
katen-ka-za [31]

Answer:

x=16

Step-by-step explanation:

Because this is an isosceles triangle the angle 2x+3 is the same as the missing angle. The angles in triangles add up to 180 degrees. 180-110=70.

Because the two angles are the same you can divide 70 by 2 to get 35.

35=2x+3.

35-3=2x+3-3

32=2x

32/2=2x/2

16=x

7 0
3 years ago
Read 2 more answers
ABC IS a right angled triangle at B and D is a point on BC. If AD=18cm , BD=9cm and CD = 4 cm, find AC
leva [86]
AB =  \sqrt{ AD^{2} - BD^{2} } =  \sqrt{243} = 9 \sqrt{3} &#10;
AC = \sqrt{ AB^{2} + BC^{2} } =  \sqrt{412} = 2 \sqrt{103}
4 0
3 years ago
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