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3 years ago

14

Which problem can be solved by division of decimals?

2 answers:

goblinko [34]3 years ago

6 0

<span>D.)What is Jeremy’s average if he received a total of 323.7 points on 7 tests?
is the answer hope this helps

</span>

Umnica [9.8K]3 years ago

5 0

Answer:

D

Step-by-step explanation:

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At Penny's Pie Shop, it costs $4 for <br> 1<br> 4<br> of a pie. What is the cost of a whole pie

sergey [27]

Answer:

16

Step-by-step explanation:

1/4 pie=4

2/4 pie= 8

3/4 pie= 12

4/4pie= 16

4 0

3 years ago

Hola, estoy empezando a ver trigonometria queria ver si me pueden ayudar con este problema: Un extraterrestre diminuto pero horr

Kryger [21]

Answer:

El agente debe disparar a un ángulo aproximado de 87.7° con respecto a la horizontal.

Step-by-step explanation:

Sea E la localización del extraterrestre, O, el del hombre de negro, y B, el de la base del edificio. A partir de la información disponible, construimos el diagrama geométrico que indica la presencia de un triángulo rectángulo, el cual puede consultarse en la imagen adjunta.

Podemos determinar el ángulo de disparo mediante la siguiente relación trigonométrica inversa:

$A = \tan^{-1} \frac{443\,m}{18\,m}$

$A \approx 87.7^{\circ}$

El agente debe disparar a un ángulo aproximado de 87.7° con respecto a la horizontal.

3 0

2 years ago

Help please! ill mark brainliest

lesya [120]

Answer:

90deg

Step-by-step explanation:

If the angles are supplementary, that means mA + mB = 180*

we know that

mA = (2x + 8)deg

mB = (2x + 8)deg = mA

mA + mB = 180deg

mB + mB = 2mB = 180deg

mB = 90deg

Note, that we did not need to compute x even, because the angles were the same.

6 0

3 years ago

There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl

insens350 [35]

We're told that

$P(A\cap B)=0.15$

$P(A\cup B)^C=0.06\implies P(A\cup B)=0.94$

$P(B\mid A)=P(B^C\mid A)=0.5$

where the last fact is due to the law of total probability:

$P(A)=P(A\cap B)+P(A\cap B^C)$

$\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)$

$\implies 1=P(B\mid A)+P(B^C\mid A)$

so that $B\mid A$ and $B^C\mid A$ are complementary.

By definition of conditional probability, we have

$P(B\mid A)=P(B^C\mid A)$

$\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}$

$\implies P(A\cap B)=P(A\cap B^C)$

We make use of the addition rule and complementary probabilities to rewrite this as

$P(A\cap B)=P(A\cap B^C)$

$\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)$

$\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)$

$\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]$

$\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]$

$\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C$

$\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)$

By the law of total probability,

$P(B)=P(A\cap B)+P(A^C\cap B)$

$\implies P(A^C\cap B)=P(B)-P(A\cap B)$

and substituting this into $(*)$ gives

$2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]$

$\implies P(B)=P(A\cup B)-P(A\cap B)$

$\implies P(B)=0.94-0.15=\boxed{0.79}$

8 0

3 years ago

Plzzzz help !!!! 15 points

ArbitrLikvidat [17]

Answer:

1. 17,20

2. 40,80

Step-by-step explanation:

1. 5+3=8

8+3=11

11+3=14

14+3=17

17+3=20

pattern is +3

2. 2.5*2=5

5*2=10

10*2=20

20*2=40

40*2=80

pattern is *2

6 0

3 years ago

Read 2 more answers