To solve this problem you will need to find the volume of the soup can (cylinder).
Volume of a cylinder: 
Plug 2 for r and 4 for h.
= 50.24 (using 3.14 for pi)
50.24 in³ of soup will fit in the can.
Answer:
93 °F
Step-by-step explanation:
At 7 am, the temperature was 55 °F + 2×7 °F = 69 °F.
At 10 am, the temperature was 69 °F + 3×8 °F = 93 °F.
Since the temperature was constant until 3 pm, it was 93 °F at noon.
Answer:
y=18.5x
Step-by-step explanation:
74-55.5=18.50
92.50-74=18.50
111-92.5=18.50
(3,55.50)
y=18.5x +b
55.50=18.5(3)+b
55.50=55.50+b
b=0
3 11/30
steps to this: here you have to Rewrite our equation with parts separated
=1+15+2+16
Solving the whole number parts
1+2=3
Solving the fraction parts
15+16=?
Find the LCD of 1/5 and 1/6 and rewrite to solve with the equivalent fractions.
LCD = 30
630+530=1130
Combining the whole and fraction parts
3+1130=31130
Solution by Formulas
First:
Convert any mixed numbers to fractions.
Then your initial equation becomes:
65+136
Applying the fractions formula for addition,
=(6×6)+(13×5)5×6
=36+6530
=10130
Simplifying 101/30, the answer is
=31130
The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
thus the lateral area will be:
L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2
The total are will be given by:
T.A=L.A+base area
base area=length*width
=4*8
=32 in^2
thus;
T.A=32+129.69
T.A=161.69 in^2
