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3 years ago

Solve for b Is it square root 39? Or Square root 89?

Mathematics

2 answers:

cricket20 [7]3 years ago

7 0

Answer:39

Step-by-step explanation:

AlladinOne [14]3 years ago

5 0

Answer:

$\sqrt{39}$

Step-by-step explanation:

By the Pythagorean Theorem:

$b^2+5^2=8^2$

We can rearrange this equation to find b:

$b^2=8^2-5^2\\\\b^2=64-25=39\\\\\sqrt{b^2}=\sqrt{39}\\\\b=\sqrt{39}$

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Nikki is playing a trivia game. At the end of the first round she has 8 points. During the second round she loses 16 points . Wh

ioda

8-16 is the answer hope this helps!

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3 years ago

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If (x + 2 ) is a factor of x3 − 6x2 + kx + 10, k =

BartSMP [9]

If a binomial x-a is a factor of a polynomial p(x), then p(a)=0.

x+2 is a factor of p(x)=x³-6x²+kx+10, so p(-2)=0.

$p(-2)=0 \\
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3 years ago

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Find A and C,Laws of sines and cosines

stealth61 [152]

Answer:

$AC=15.9976$

Step-by-step explanation:

Law of Sines: $\frac{sin(A)}{a} =\frac{sin(B)}{b} =\frac{sin(C)}{c}$

Step 1: Define

a = 8 ft

A = 30°

b = ?

B = 89°

Step 2: Substitute and Evaluate

$\frac{sin(30)}{8} =\frac{sin(89)}{b}$

$bsin(30)=8sin(89)$

$b=\frac{8sin(89)}{sin(30)}$

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3 years ago

Whole numbers greater than 9 but less than 14

yaroslaw [1]

10, 11, 12, and 13 :)

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3 years ago

<img src="https://tex.z-dn.net/?f=4%20%20%20%7B%7D%5E%7Bx%20%7D%20%20%2B%206%20%7B%7D%5E%7Bx%7D%20%3D%209%20%7B%7D%5E%7Bx%7D%20%

Nookie1986 [14]

So, the value of x is 1.19

The question is an exponential equation

<h3>What is an exponential equation?</h3>

An exponential equation is a mathematical expression between two quantities in which one variable is raised to a power of the other variable.

Since $4^{x} + 6^{x} = 9^{x}$ ,

Dividing through by 4ˣ, we have

$\frac{4^{x} }{4^{x} } + \frac{6^{x} }{4^{x} } = \frac{9^{x} }{4^{x} } \\1 + (\frac{6}{4})^{x} } = (\frac{9}{4})^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3^{2} }{2^{2} })^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3}{2})^{2x} }$

Let y = (3/2)ˣ

So,

1 + y = y²

y² - y - 1 = 0

Using the quadratic formula to find y,

$y = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

where a = 1 b = -1 and c = -1

Substituting the values of the variables into the equation, we have

$y = \frac{-(-1) +/- \sqrt{(-1)^{2} - 4\times 1 \times (-1)} }{2\times 1}\\= \frac{1 +/- \sqrt{1 + 4} }{2}\\= \frac{1 +/- \sqrt{5} }{2}\\= \frac{1 - \sqrt{5} }{2} or \frac{1 + \sqrt{5} }{2}\\= \frac{1 - 2.236}{2} or \frac{1 + 2.236}{2}\\= \frac{- 1.236}{2} or \frac{3.236}{2}\\= -0.618 or 1.618$

Since y = (3/2)ˣ

Takung logarithm of both sides, we have

㏒y = ㏒(3/2)ˣ

㏒y = x㏒(3/2)

x = ㏒y/㏒(3/2)

x = ㏒y/㏒1.5

Since we do not have logarithm of a negative number, we use y = 1.618.

So, x = ㏒y/㏒1.5

x = ㏒1.618/㏒1.5

x = 0.2090/0.1761

x = 1.19

So, the value of x is 1.19

Learn more about exponential equation here:

brainly.com/question/11832081

#SPJ1

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1 year ago