Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Here, You need to apply "Proportionality Theorem"
According to this theorem, the ratio of components of a leg would be equal to the ratio of corresponding components of another leg.
In mathematical form,
TV/VS = TW/WU
Substitute their values,
14/6 = 21/(x+4)
14(x+4) = 21*6
14x+56 = 126
14x = 126-56
x = 70/14
x = 5
In short, Your Answer would be 5
Hope this helps!
Answer:
running a two year contract is the best i have to do with my life in this world and it has a great way to go through the
A I think idk what I am doing it’s w.e
the answer is 1 2 and 3 because they cant be divided by anything
