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3 years ago

5

HURRY I NEED HELP!!!!!

1 answer:

Daniel [21]3 years ago

3 0

Answer:

<h3><em><u>hey</u></em><em><u> </u></em><em><u>mate</u></em><em><u> </u></em><em><u>here</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>ur</u></em><em><u> </u></em><em><u>answer</u></em><em><u>:</u></em><em><u>---------------------------------------------------</u></em></h3>

<h3><em><u>1) f (x) = x 3 + 2x 2 - 8x first factor of x ------> x( x^2 +2x -8) = 0 -------> x = 0 and x^2 +2x -8 = 0</u></em></h3><h3 /><h3><em><u>1) f (x) = x 3 + 2x 2 - 8x first factor of x ------> x( x^2 +2x -8) = 0 -------> x = 0 and x^2 +2x -8 = 0 Now, you find b^2 -4ac that in this case will be = 2^2 -4*1*(-8) = 4 + 32 = 36 it means this equation has 2 different real roots and will be (-b ±√b^2 - 4ac) / 2a ------> x = 2 , -4 as result #1 has 3 real roots such as 0,2,-4</u></em></h3>

<h3><em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>u</u></em><em><u> </u></em></h3><h3><em><u>have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>nice</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em><em><u>✌</u></em></h3>

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1<br> -<br> 2 x(x-2x+4<br> Ayuda

vova2212 [387]

Answer:

Simplified - 2x(-x+4), Solution - -2x(-x+4)

4 0

3 years ago

The circle described by the equation <img src="https://tex.z-dn.net/?f=%28x-3%29%5E%7B2%7D%20%2B%28y%2B4%29%5E%7B2%7D%3D9" id="T

ElenaW [278]

Answer:

The point at which center of the image circle located is (-2, -3) so second option is correct.

Step-by-step explanation:

Given equation of circle is:

$(x-3)^{2} + (y+4)^{2} = 9$ (i)

The general equation of circle is mentioned below,

$(x-h)^{2} + (y-k)^{2} = r^{2}$ (ii)

Here 'r' represents the radius of the circle and (h,k) shown the center of the circle.

By comparing equation (i) and equation (ii), we get

r^2 = 9

r = 3

$(x-3)^{2} = (x-h)^{2}$

$(x-3) = (x-h)$

$h = 3$

$(y+4)^{2} = (y-k)^{2}$

$(y+4) = (y-k)$

$k = -4$

So the center of given circle is (h,k) = (3,-4)

Also, the circle is translated 5 units left, that is towards the -x-axis. Therefore h = 3 - 5 = -2

Also, the circle is translated 1 unit up, that is towards the +y-axis. Therefore k = -4 + 1 = -3

Hence, the point at which center of the image circle located is (-2, -3) so second option is correct.

6 0

3 years ago

Read 2 more answers

For any two integers a and b, (a + b)² = a² + b²

kozerog [31]

Answer:

wrong

Step-by-step explanation:

(a+b)^2=(a+b)(a+b)

=a(a+b)b(a+b)

=a^2+ab+ab+b^2

=a^2+2ab+b^2

i hope it helps you

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4 years ago

List all the factors of 16

Ronch [10]

Answer:

1,2,4,8,16

Step-by-step explanation:

prime factorization: 2x2x2x2 =16

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3 years ago

A restaurant charges `\$3` for `8` cookies.A restaurant charges `\$3` for `8` cookies. At this rate, how much would it cost to b

butalik [34]

Answer:

i think its like 10 to 12$

Step-by-step explanation:

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