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3 years ago

5

HURRY I NEED HELP!!!!!

1 answer:

Daniel [21]3 years ago

3 0

Answer:

<h3><em><u>hey</u></em><em><u> </u></em><em><u>mate</u></em><em><u> </u></em><em><u>here</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>ur</u></em><em><u> </u></em><em><u>answer</u></em><em><u>:</u></em><em><u>---------------------------------------------------</u></em></h3>

<h3><em><u>1) f (x) = x 3 + 2x 2 - 8x first factor of x ------> x( x^2 +2x -8) = 0 -------> x = 0 and x^2 +2x -8 = 0</u></em></h3><h3 /><h3><em><u>1) f (x) = x 3 + 2x 2 - 8x first factor of x ------> x( x^2 +2x -8) = 0 -------> x = 0 and x^2 +2x -8 = 0 Now, you find b^2 -4ac that in this case will be = 2^2 -4*1*(-8) = 4 + 32 = 36 it means this equation has 2 different real roots and will be (-b ±√b^2 - 4ac) / 2a ------> x = 2 , -4 as result #1 has 3 real roots such as 0,2,-4</u></em></h3>

<h3><em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>u</u></em><em><u> </u></em></h3><h3><em><u>have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>nice</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em><em><u>✌</u></em></h3>

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