Answer:
(a)
(b)
(c)
(d)
(e)
(f)
Step-by-step explanation:
Let as consider the given equations are
.
(a)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(b)
![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(c)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(d)

![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(e)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(f)


![[\because \log10^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog10%5Ex%3Dx%5D)
Answer:
<u><em>x>2</em></u>
Step-by-step explanation:
<u><em>x3+3x2=7x+6</em></u>
<u><em>x3+3x2−(7x+6)=7x+6−(7x+6)</em></u>
<u><em>x3+3x2−7x−6=0</em></u>
<u><em>(x−2)(x2+5x+3)=0</em></u>
<u><em>x−2=0 or x2+5x+3=0</em></u>
<u><em>x=2 or x=−0.6972243622680054 or x=−4.302775637731995</em></u>
<u><em>x<−4.302776</em></u>
<u><em>−4.302776<x<−0.697224</em></u>
<u><em>−0.697224<x<2</em></u>
<u><em>x>2(Works in original inequality)</em></u>
Answer:
x + 3 = 0.
Step-by-step explanation:
One would be:
x + 3 = 0 Subtract 3 from both sides:
x + 3 - 3 = 0 - 3
x = -3
Answer:
x = 5.5
Step-by-step explanation:
- 6-(2x-4)+x = 6-2x+4+x = 10-x
- 3(x-4) = 3x-12
- Based on the 1st and the 2nd steps, 10-x=3x-12 --> 10+12=3x+x --> 22 = 4x --> x =22/4 = 5.5