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Naddika [18.5K]
3 years ago
7

The function f(x) = 1/2x + 3/2 is used to complete this table. Which statements are true of the given function? Check all that a

pply.
the numbers on the table are. (-1,1) (0,2/3) (1,2) (2,5/2)
​

Mathematics
2 answers:
allochka39001 [22]3 years ago
4 0
I don’t know whisking you the best of luck
lyra2 years ago
0 0

Answers:
It's f(0)= 3/2
and f(4)=7/2

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What is 3^(3/2) equal to
Delicious77 [7]
It equals 5.1962.... If it's 3/2 then you can do 3 divided by 2 and you'll get 1.5. If you have a scientific calculator you can do 3 to the power of 1.5 which will get you your answer.
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Find the 4th term of the expansion of (x+2)^5.​
djyliett [7]

Answer:(2x + 5)⁵

Step-by-step explanation:I assume you mean the 4th term of the expansion of (2x + 5)⁵. The coefficient can be found from pascal's triangle.

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Hey! i’ll give brainliest please help
myrzilka [38]

Answer:

The 4th answer

Step-by-step explanation:

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Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

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3 years ago
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andreev551 [17]

Answer:2-6

Step-by-step explanation:

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