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yawa3891 [41]
3 years ago
9

Convert 7/9 into its decimal form and round to the nearest thousandth

Mathematics
2 answers:
AlexFokin [52]3 years ago
8 0

Answer:

0.778

Step-by-step explanation:

You divide 7 by 9 which would give you a repeating decimal. But after you round it, it would be 0.778

professor190 [17]3 years ago
5 0

Answer:

0.778

Step-by-step explanation:

7 divided by 9 is 0.77777777777.

Rounded to the thousandth place is 0.778.

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Marcus drew a quadrilateral with only 1 pair of parallel sides. Which quadrilateral did Marcus draw? A. rhombus B. parallelogram
babunello [35]
NOOO! It's a trapezoid
7 0
4 years ago
8. Combine the like terms in this expression: –3x + 2xy + 4y – xy + 2x – 11y
luda_lava [24]

Answer:

D. –X+XY–7y

Step-by-step explanation:

We just have to combine (add) the similar terms... so all terms that have an x in them for example.

–3x + 2xy + 4y – xy + 2x – 11y

Let's first re-write it placing similar terms next to each other

(-3x + 2x) + (2xy - xy) + (4y - 11y)

Then we sum them up, for each similar terms

1x + 1xy -7y

so, x + xy -7y

Answer D.

6 0
3 years ago
most people lose 100 to 200 hairs per day. if you were to lose 150 hair per day for 10 days, what would be the change in the num
QveST [7]

Answer:

-1500 hairs

Step-by-step explanation:

You lose 150 hairs for 10 days

150 * 10 = 1500 hairs

The change is lose of hair so it is negative

-1500 hairs

8 0
3 years ago
Read 2 more answers
In ΔMNO, the measure of ∠O=90°, the measure of ∠M=74°, and OM = 5.4 feet. Find the length of NO to the nearest tenth of a foot.
jeka94

Answer:

18.8 feet

Step-by-step explanation:

\tan M = \frac{\text{opposite}}{\text{adjacent}}=\frac{x}{5.4}

tanM=

adjacent

opposite

​

=

5.4

x

​

\tan 74=\frac{x}{5.4}

tan74=

5.4

x

​

5.4\tan 74=x

5.4tan74=x

Cross multiply.

x=18.832\approx \mathbf{18.8}\text{ feet}

x=18.832≈18.8 feet

Type into calculator and roundto the nearest tenth of a foot.

M

N

O

5.4

18.8

(adjacent to ∠M)

(opp. of ∠M)

(hypotenuse)

74°

4 0
3 years ago
F the height remains fixed and the side of the base is decreasing by 0.002 meter/yr, what rate is the volume decreasing when the
katrin [286]

The original volume equation looks like this: V = 1/3 * h * (x^2) 
After the side is reduced by 0.002, the new volume would look like V1 = 1/3 * h * (x-0.002) ^ 2 

Then we have: 
V-V1 = 1/3*h*(x^2) - 1/3*h*(x – 0.002) ^2 


= 1/3 * h *(x^2 - (x – 0.002) ^2) 


= 1/3 * h * (0.004x - 0.00004) 


The rate of decreasing is computed by:


(V-V1)/V * 100% = [1/3 * h *(0.004x - 0.00004)] / [1/3 * h * (x ^ 2)] * 100% this would be equal to (0.004x - 0.00004) / (x^2) * 100% 

So replace x by 200, you’ll get:

(0.004(200) - 0.00004) / (200^2) * 100% 

= 0.001999% is the rate of decreasing.

4 0
4 years ago
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