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Jlenok [28]
3 years ago
12

A baseball team played 154 regular season games. The ratio of the number of games they won to the number of games they lost was

4/3. How many games did they​ win? How many games did they​ lose
Mathematics
1 answer:
Fittoniya [83]3 years ago
7 0

Answer:

88 won and 66 lost

Step-by-step explanation:

Won = \frac{154}{4+3}×4 = 88 games

Lost = 154 - 88 = 66 games

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A rectangle is placed around a semicircle as shown below. The length of the rectangle is 8 cm. Find the area of the shaded regio
icang [17]

Answer:

Area of the shaded region = 6.88 cm²

Step-by-step explanation:

Area of the shaded region = Area of the rectangle - Area of the semicircle

Area of the rectangle = Length × Width

Length of the rectangle = AD = 8 cm

Width of the rectangle = OP = 4 cm [OP, OB and OC are the radii of the circle which are equal in measures]

Area of the rectangle = 8 × 4 = 32 cm²

Area of the semicircle = \frac{1}{2}\pi r^{2}

                                     = \frac{1}{2}\pi (OP)^{2}

                                     = \frac{1}{2}\pi (4)^{2}

                                     = 25.12 cm²

Area of the shaded region = 32 - 25.12

                                              = 6.88 cm²

3 0
3 years ago
Yuvia also earns a base salary of $45 per day. What is the total amount she earned that day? [Total Salary = Base Pay + Commissi
andriy [413]
The answer you need is $245
5 0
3 years ago
Read 2 more answers
Sovlve the equation. Show work.
Rainbow [258]

Answer:

x = 10

Have a good day! Brainliest?

3 0
3 years ago
Read 2 more answers
How do i solve this?
bearhunter [10]

Order them from least to greatest  47,65,67

8 0
4 years ago
Un grupo de estudiantes tiene como proyecto final determinar el grado de aceptación de las amas de casa de cierto sector de la c
Dafna11 [192]

Usando la distribución binomial, se encuentra que hay una probabilidad de 0.0022 = 0.22% que exactamente 5 de las amas de casa prefieran la presentación de 1500 gramos.

Para cada estudiante, solo hay dos resultados posibles. O prefieren la presentación de 500 gramos, o prefieren la de 1500 gramos. La decisión de cada estudiante es independiente de otros estudiantes, o que implica que se usa la distribuición binomial.

Distribuición binomial.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}  

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son :

  • n es el número de ensayos.
  • x es la probabilidad de éxito en una sola prueba.
  • p es la probabilidad de éxito en un solo ensayo.

En este problema:

  • 20 amas de casa, o sea, n = 20.
  • 5% prefieren lo detergente de 1500 gramos, o sea, p = 0.05.
  • La probabilidad de exactamente 5 es P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{20,5}.(0.05)^{5}.(0.95)^{15} = 0.0022

Probabilidad de 0.0022 = 0.22% que exactamente 5 de las amas de casa prefieran la presentación de 1500 gramos.

Un problema similar es dado en brainly.com/question/22304471

5 0
3 years ago
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