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defon
3 years ago
14

What is the surface area ?

Mathematics
1 answer:
exis [7]3 years ago
4 0

Answer:

A=2(wl+hl+hw)=2·(6·14+5·14+5·6)=368

Step-by-step explanation:

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4+ y = 10<br> What is the answer and how do I solve it
julia-pushkina [17]

Answer:

y=6

Step-by-step explanation:

4+y=10

-4     -4

   y=6

just subtract 4 from both sides

8 0
3 years ago
A parabola intersects the xxx-axis at x=3x=3x, equals, 3 and x=9x=9x, equals, 9.
hichkok12 [17]

Answer:

x=6

Step-by-step explanation:

Given the x-intercepts of a parabola: x_1=3, x_2=9

The equation of symmetry at the parabola's vertex is x=h

Where h=\dfrac{x_1+x_2}{2}

In this case,

h=\dfrac{3+9}{2}=6

Therefore, the line of symmetry of the parabola is x=6 and is also the x-coordinate of the parabola's vertex.

8 0
4 years ago
An equilateral triangle has an altitude length of 33 feet. Determine the length of a side of the triangle.
Murrr4er [49]
The side of this triangle is about 23.3345237792
4 0
3 years ago
You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
2 years ago
Round $5.127 to the nearest hundredths​
Soloha48 [4]

Answer:

$5.13

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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