The velocity of the bus is:
velocity (bus) = 36 miles / 40 min
velocity (bus) = 0.9 miles / min
Since the car is 1.5 times faster, so the velocity of the
car is:
velocity (car) = 1.5 * 0.9 miles / min
velocity (car) = 1.35 miles / min
At the meeting point, the sum of the distance is equal to
36 miles. Therefore:
1.35 t + 0.9 t = 36
2.25 t = 36
t = 16 min
So they will meet after 16 minutes.
Answer:
3.78
Step-by-step explanation:
Percentage solution with steps:
Step 1: We make the assumption that 9 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$.
Step 3: From step 1, it follows that $100\%=9$.
Step 4: In the same vein, $x\%=42$.
Step 5: This gives us a pair of simple equations:
$100\%=9(1)$.
$x\%=42(2)$.
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{9}{42}$
Step 7: Taking the inverse (or reciprocal) of both sides yields
$\frac{x\%}{100\%}=\frac{42}{9}$
$\Rightarrow x=466.67\%$
Therefore, $42$ is $466.67\%$ of $9$.
Step-by-step explanation:
8=1,2,4,8.
12=1,2,3,4,6.
18=1,2,3,6,9.
so 2 is common and lowest in everyone.
answer is 2
<u><em>y=1</em></u> this is because in rise/run the point rises 2 and moves to the right 1 and following this backwards leads to y=1
Thus an approximate 95% confidence interval for the average enrollment of all 60,000 faculty members in the two years prior to the survey. which implies that the given statement is true.
According to the statement
Average sample =3700
SD sample =6500
Sample size =400
EV average =3700
SE average =325
Population size =3000
The boundaries of the 68% confidence interval are then 1 standard error from the estimated average:
EV average+1⋅SE average =3700+1⋅325=3700+325=4025
EV average−1⋅SE average =3700−1⋅325=3700−325=3375
Thus an approximate 95% confidence interval for the average enrollment of all 60,000 faculty members in the two years prior to the survey. which implies that the given statement is true.
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