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DerKrebs [107]
2 years ago
12

Which statement is correct for the graph of the specified function?

Mathematics
1 answer:
mash [69]2 years ago
4 0

The correct statement regarding the function plotted in the graph is:

C) The maximum value of the quadratic function occurs at y = 4.

<h3>What is the rate of change of the linear function?</h3>

When x = 0, y = -7, and when x = -5, y = 8, hence the rate of change(change in y divided by change in x) is given by:

R = [8 - (-7)]/-5 - 0 = 15/-5 = -3

<h3>What is the maximum value of the quadratic function?</h3>

It is concave down, hence it has only a maximum value at y = 4 and not a minimum value, hence option C is correct.

More can be learned about functions at brainly.com/question/25537936

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Find the annual rate of interest. Principal = 4600 rupees, Period = 5 years, Total amount = 6440 rupees, Annual rate of interest
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The annual rate of interest per year is 8%

<u>Solution:</u>

Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees

First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest

Interest = Amount – Principal

Interest = 6440  – 4600 = 1840

Now using the formula of simple Interest and on putting values we get,

\text {Simple Interest }=\frac{P \times R \times T}{100}

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period

1840=\frac{4600 \times R \times 5}{100}

\begin{aligned} \mathrm{R} &=\frac{1840 \times 100}{4600 \times 5} \\\\ \mathrm{R} &=\frac{1840}{230} \\\\ \mathrm{R} &=8 \% \end{aligned}

Hence, the required rate of interest per year is 8%

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DENIUS [597]
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Answer:

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Hope this helps!
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