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Rudiy27
3 years ago
6

Round to the nearest tenth if necessary.

Mathematics
1 answer:
Andrei [34K]3 years ago
4 0

Answer:

B) 25

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (-1, -8)

Point (-4, -4)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(-4--1)^2+(-4--8)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{(-3)^2+(4)^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{9+16}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{25}
  5. [√Radical] Evaluate:                                                                                           \displaystyle d = 5
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Answer

Find out the what is the value of x when y = 8 .

To prove

As given

The variables y and x have a proportional relationship.

y \propto x

y = kx

Where k is the constant of proportionality.

As y = 5 when x = 4

Put in the above

5 = 4k

k = \frac{5}{4}

Now find out the value of x , when y = 8

8 = \frac{5\times x}{4}

x = \frac{8\times 4}{5}

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Answer:

  • <em>The probability that the second favorite character will die given that the first favorite character dies is</em><u> 0.53</u>

  • <u>This kind of probability is called conditional probability</u>

Explanation:

Name the events and their probabiities:

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Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
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Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

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Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

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The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

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\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

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Answer:

<6

Step-by-step explanation:

Corresponding angles have the same matching corner when a transversal line crosses tow straight lines.

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<6 has the same matching corner with <2.

Therefore, <6 corresponds with <2

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