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Gekata [30.6K]
2 years ago
12

Please help me solve this question will give you braisnlt !

Mathematics
1 answer:
pickupchik [31]2 years ago
5 0

Answer:

t = 54 m + 160

Step-by-step explanation:

I can do the whole explanation unless you just need the answer that's the correct answer

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Marj needs to round $345.67$, and she wants the result to be as large as possible. She has to round to the nearest thousand, the
Andre45 [30]

Answer:

$346.00

Step-by-step explanation:

4 0
2 years ago
What is 144 divided by 18 in the distributive property
kvv77 [185]
=(140+4) / 8
=(144/8) + (4/8)
=18 + 2
=<span>20</span>
8 0
3 years ago
The school that Lisa goes to is selling tickets to the annual talent show. On the first day of ticket sales the school sold 4 se
kakasveta [241]
Let:
x = cost of senior citizen ticket
y = cost of student ticket

4x + 5y = 102
7x + 5y = 126

4x + 5y = 102
4x = 102 - 5y
x = (102 - 5y)/4
x = 102/4 - 5y/4

7x + 5y = 126
7(102/4 - 5y/4) + 5y = 126
(714/4 - 35y/4) + 5y = 126
-35y/4 + 5y = 126 - 714/4

note:
-35y/4 = -8.75y
714/4 = 178.5

-8.75y + 5y = 126 - 178.5
-3.75y = -52.5
y = -52.5/-3.75
y = 14


x = 102/4 - 5y/4
x = 102/4 - 5(14)/4
x = 8

x = cost of senior citizen ticket = $8/ea
y = cost of student ticket = $14/ea



6 0
3 years ago
I NEED HELP PLEASE ASAP! :)
bonufazy [111]

Answer:

See below.

Step-by-step explanation:

Again, another great question!

This should be under physics, as it involves Work = Force * Distance. As Anne pushes the wheelbarrow with a force of 70 Newtons with respect to an angle of 50 degrees horizontal, the horizontal force is 70( cos 50 ). The distance over which the work is done is 25 meters, so work should be -

Work = ( 70( cos 50 ) )( 25 ),

Work = ( About ) 1124.87 Joules

<u><em>The work done when Anne pushes the wheelbarrow a distance of 25 meters, is 1124.87 Joules</em></u>

6 0
3 years ago
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
3 years ago
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