It's going to be a 3x2. Im assuming its [ 5 10 on the first row, second row would be -2, -4, then the bottom row would be 1, 2] Hope I helped!
For my answer, I got -47 1/2
c is the answer cuz a is a straight line of dots b is a no solution plot and d is a poitive plot
Answer:
y = 2x + -5
Step-by-step explanation:
If you look at the graph, you can find that the slope is 2/1 which is simply just a slope of 2. The y-intercept can be found x = 0, so plug in 0 for x, solve from there and you get -5 for the y-intercept.
Step-by-step explanation:
The displacement of a particle d (in km) as a function of time t (in hours) is given by :
![d=2t^3+5t^2-3](https://tex.z-dn.net/?f=d%3D2t%5E3%2B5t%5E2-3)
Displacement at t = 4 hours,
![d(4)=2(4)^3+5(4)^2-3=205\ km](https://tex.z-dn.net/?f=d%284%29%3D2%284%29%5E3%2B5%284%29%5E2-3%3D205%5C%20km)
Velocity of particle is given by :
![v=\dfrac{dd}{dt}\\\\v=\dfrac{d(2t^3+5t^2-3)}{dt}\\\\v=6t^2+10t](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bdd%7D%7Bdt%7D%5C%5C%5C%5Cv%3D%5Cdfrac%7Bd%282t%5E3%2B5t%5E2-3%29%7D%7Bdt%7D%5C%5C%5C%5Cv%3D6t%5E2%2B10t)
Velocity at t = 4 hours,
![v=6(4)^2+10(4)=136\ km/h](https://tex.z-dn.net/?f=v%3D6%284%29%5E2%2B10%284%29%3D136%5C%20km%2Fh)
Acceleration of the particle is given by :
![a=\dfrac{dv}{dt}\\\\a=\dfrac{d(6t^2+10t)}{dt}\\\\a=12t+10](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bdv%7D%7Bdt%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7Bd%286t%5E2%2B10t%29%7D%7Bdt%7D%5C%5C%5C%5Ca%3D12t%2B10)
At t = 4 hours,
![a=12(4)+10=58\ km/h^2](https://tex.z-dn.net/?f=a%3D12%284%29%2B10%3D58%5C%20km%2Fh%5E2)
Therefore, the displacement, velocity and acceleration at t = 4 hours is 205 km, 136 km/h and 58 km/h² respectively.