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3 years ago

Am nevoie de ajutor cu acest test!!!

Mathematics

2 answers:

nydimaria [60]3 years ago

6 0

Answer:

128409600 Oentr

pentru ca 20×5=100

sweet-ann [11.9K]3 years ago

4 0

Answer: C
Sorry if wrong

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How do I put this in slope intercept form y=-x/3 +4

konstantin123 [22]

Slope Intercept form is y=mx+b. They are already in that form. The x is in the numerator because the fractions multiply by x, so...
y=-1/3(x)+1 and y=1/2(x)-4
Hope this helps.

5 0

4 years ago

mario earns a weekly salary of $440.00 plus a 12% commission on any sales. this week he sold $525.00 worth of merchandise. how m

My name is Ann [436]

Answer:

10% of 440.00=44

1%(÷by 100) of 440.00=4.40

1%=4.40

then do 44+4.40+4.40=52.80(that is 12% comission)

then you add 12% of 440 onto his weekly salary that equals to 492.8

this week he sold 525.000

12%of 525.00=63

then add 63 to 440=503

so Rany eartn $503

8 0

3 years ago

I need to know the answer I got cancer and I fell tired and I need to do this and no one is helping me

Sergeeva-Olga [200]

AZ = 1.5 inches ( 1 and a half inches)

3 0

2 years ago

Can someone solve this equation for me?

Serggg [28]

Answer:

x=6

Step-by-step explanation:

LCM of 3,2 : 6

(4/6)x + (3/6)x = 7

(7/6)x =7

(divide 7/6 on both sides)

x= 6

6 0

3 years ago

The shuttle bus from your parking lot and your office building operates on a 15 minute schedule. You arrive at the parking lot a

mylen [45]

Answer:

(a) The standard deviation of your waiting time is 4.33 minutes.

(b) The probability that you will have to wait more than 2 standard deviations is 0.4227.

Step-by-step explanation:

Let X = the waiting time for the bus at the parking lot.

The random variable X is uniformly distributed with parameters a = 0 to b = 15.

The probability density function of X is given as follows:

$f_{X}(x)=\frac{1}{b-a};\ a$

(a)

The standard deviation of a Uniformly distributed random variable is given by:

$SD=\sqrt{\frac{(b-a)^{2}}{12}}$

Compute the standard deviation of the random variable X as follows:

$SD=\sqrt{\frac{(b-a)^{2}}{12}}$

$=\sqrt{\frac{(15-0)^{2}}{12}}$

$=\sqrt{\frac{225}{12}}$

$=\sqrt{18.75}\\=4.33$

Thus, the standard deviation of your waiting time is 4.33 minutes.

(b)

The value representing 2 standard deviations is:

$X=2\times SD=2\times4.33=8.66$

Compute the value of P (X > 8.66) as follows:

$P(X>8.66)=\int\limits^{10}_{8.66} {\frac{1}{15-0}}\, dx\\$

$=\frac{1}{15}\times \int\limits^{10}_{8.66} {1}\, dx\\$

$=\frac{1}{15}\times |x|^{15}_{8.66}\\$

$=\frac{15-8.66}{15}\\$

$=0.4227$

Thus, the probability that you will have to wait more than 2 standard deviations is 0.4227.

4 0

3 years ago