it’s b because it oooks like b
Answer:
25/3 ft/s
Step-by-step explanation:
Height of pole , h=15 ft
Height of man, h'=6 ft
Let BD=x
BE=y
DE=BE-BD=y-x
All right triangles are similar
When two triangles are similar then the ratio of their corresponding sides are equal.
Therefore,
Differentiate w.r.t t
We have dx/dt=5ft/s
Using the value
Hence, the tip of his shadow moving with a speed 25/3 ft/s when he is 45 feet from the pole.
Answer:
81
Step-by-step explanation:
Substitute 3 in place of y
7 * 3 * 3 - 16 + 5 * 3 *2 + (16 / 4)
63 - 16 + 30 + 4
Answer:
Step-by-step explanation:
Here we have KP = PE (tangents from outside the circle)
Therefore, 2KP = PE + 1 = KP + 1
Hence, 2KP - KP = 1 or KP = 1 = PE
Since KE is the base of triangle KPE, where ∡ KPE = 60, and KP = PE, we have an isosceles triangle such that ∡PKE = ∡PEK
Hence, in ΔKPE, ∡KPE + ∡PKE + ∡PEK = 180
Therefore, 60° + ∡PKE + ∡PEK = 180
Hence, ∡PKE + ∡PEK = 180° - 60° = 120°
Because ∡PKE = ∡PEK, (base angles of isosceles triangle), we have;
∡PKE + ∡PEK = 2·∡PEK = 120° which gives
∡PEK = 60° = ∡PKE
Therefore, ∡KPE = ∡PEK = ∡PKE = 60°
Hence, ΔKPE is an equilateral triangle and KP = PE = EK = 1
EK = 1.
Answer:
See Explanation
Step-by-step explanation:
Given
--- Number of tryouts
Required
Determine the average distance
<em>This question has missing details, as the distance he hits the ball in each tryout is not given. However, I'll give a general explanation.</em>
<em></em>
The mean is calculated as:
means the sum of the distance in each tryout.
Assume that the distance in the 10 tryouts are:
So, the mean is:
<em>So, the average distance is 6.5</em>