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borishaifa [10]
3 years ago
11

Pls help me solve this

Mathematics
1 answer:
melamori03 [73]3 years ago
8 0

Answer:

See below.

Step-by-step explanation:

1.) False - It contains 6 sig figs, not 2.

2.) False - It goes up to 2 decimal places, not 3.

3.) True

4.) False - It goes up to 1 sig fig, not 4.

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F(x)=(5x+1)(4x−8)(x+6)f, left parenthesis, x, right parenthesis, equals, left parenthesis, 5, x, plus, 1, right parenthesis, lef
andrey2020 [161]

Answer:

x=-\frac{1}{5}  \:or \: x=2 \:or\: x=-6

Step-by-step explanation:

Given f(x)=(5x+1)(4x-8)(x+6)

The zeros of the polynomial function are the point where the function f(x) equals zero.

f(x)=(5x+1)(4x-8)(x+6)=0

If abc=0, then a=0 or b=0 or c=0

Therefore:

(5x+1)(4x-8)(x+6)=0 \:means\\5x+1=0 \:or \: 4x-8=0 \:or\: x+6=0\\5x=-1 \:or \: 4x=8 \:or\: x=-6\\x=-\frac{1}{5}  \:or \: x=2 \:or\: x=-6

6 0
3 years ago
What is the value of the underlined digit?
blondinia [14]

Answer:

i think is ten million (B)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The number of users on a website has grown exponentially since its launch. After 2 months, there were 90 users. After 4 months,
grigory [225]

Answer:

10(3)^x

Step-by-step explanation:

The function contains the points (2,90) and (4,810). Use the general form y=abx to write two equations:

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Solve each equation for a:

a=90/b^2 and a=810/b^4

Since a=a, set the other sides of the equations equal and solve for b.

90/b2=810/b4

Cross multiply, then divide and simplify as follows:

90b^4=810b^2

b^4/b^2=810/90

b^2=90

b^3

Now, use the value of b and the point (2,90) to find the value of a.

90=a(3^2)

a=10

So, substitute answers in original equation for a final answer of f(x)=10(3)^x.

8 0
3 years ago
Round to the tenths place .712 .665 .545
Artyom0805 [142]

.712 rounds to .7

.665  rounds to .7

.545 rounds to .5

5 0
3 years ago
Part E
Rina8888 [55]

Answer:

Step-by-step explanation:

OK you should really have these by now.

Translation, reflection and rotations do not change segment lengths or angular relationships. They only change line slopes and/or y-intercepts.

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2 years ago
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