Segment AB and segment BC are tangent to circle D. Find x if AB = 5x + 11 and BC = 3x + 25.
2 answers:
we know that tangents in a circle intersecting at point is always equal in length. we have two tangents AB and BC
by theorm AB=BC
5x+11=3x+25
2x=14
x=7. the length of x is 7
If two tangents drawn on a circle from the same external point then the tangents will be equal.
Here AB and BC are the two tangents of the circle drawn from a point B. So,
AB= BC.
Given AB = 5x + 11 and BC = 3x + 25. Hence, we can set up an equation as following:
5x + 11 = 3x + 25
5x + 11 -3x = 3x + 25 -3x By subtracting 3x from each sides.
2x + 11 = 25
2x + 11 - 11 = 25 - 11 By subtracting 11 from both each sides.
2x = 14
Dividing each sides by 2.
So, x= 7
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32.6 ft/s and approximately 0.03 s/ft
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